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New Superconductor Found "Immune To Magnetism" 201

Lisandro sends in news that testing of the new class of superconductors we discussed a while back (compounds of iron, lanthanum, and rare earths) has turned up a major surprise: magnetism doesn't shut off the superconducting state. Magnetic fields represent one of three factors that limit expanded applications for superconductors (the others are current density and temperature dependence.) The research will appear in Nature; here's a preprint (PDF).
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New Superconductor Found "Immune To Magnetism"

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  • Another limit? (Score:3, Informative)

    by abbamouse ( 469716 ) on Tuesday June 03, 2008 @02:41PM (#23642611) Homepage
    I seem to recall that one limit was simply the ceramic nature of most superconductors. If it isn't ductile, you can't use it for wires -- which are kind of important for most superconducting applications. Am I wrong about this?
    • I would imagine that you could support the superconductor material with something significantly stronger
      • Bussard Ramjets! (Score:5, Insightful)

        by StCredZero ( 169093 ) on Tuesday June 03, 2008 @03:52PM (#23643599)
        Superconductors that are immune to interference from magnets would get us further towards Bussard Ramjets. There are other hurdles, like the mechanical strength of the magnetic coils themselves. (So the magnetic forces don't wreck them.) Even if we couldn't make practical ramjets, magnetic sails would also benefit, which would make deceleration of interstellar craft almost "free."

        http://en.wikipedia.org/wiki/Bussard_ramjet [wikipedia.org]
        • by Ungrounded Lightning ( 62228 ) on Tuesday June 03, 2008 @07:32PM (#23646057) Journal
          A somewhat off-topic digression:

          The conventional wisdom on Bussard Ramjets (included in the wikipedia article) is that they reach a terminal velocity due to the drag of collecting the fuel - and asymptotically approach their exhaust velocity. IMHO that's incorrect.

          The bug is that the calculation assumes that they must accelerate the collected hydrogen to the velocity of the craft before fusing it, then depend on the fusion energy to re-accelerate it as exhaust.

          However, as with the collected air in chemical ramjets, the momentum of the collected material does not need to be discarded. It can be fused on the fly through the ramjet, retaining its original momentum along the flight path (relative to the vessel). Thus the energy of fusion can be applied to accelerating the reaction products toward the rear. None is needed to replace the momentum allegedly lost capturing the fuel.

          Now SOME of the axial momentum of the incoming fuel is traded for radial momentum to collect it. But the energy of that "lost" momentum is converted to pressure and temperature, compressing the material like any other gas. There is a drag on the scoop field from this. But when the exhaust expands again after the reaction there is a corresponding thrust against the nozzle field, reconverting the radial expansion of the reaction products to rearward velocity and recovering the "lost" momentum.

          If this whole process were lossless there would be no top end to the kenetic energy the ramscoop could accumulate. With less than 100% efficiency in reapplying the compression energy to the mass (both from lost energy and lost mass) there is some drag from collection that is not recovered. (For instance: Mass lost as neutrinos is a non-trivial fraction.) So there may still be a speed limit. But it can be far higher than that calculated by assuming you "stopped" the gas when you "caught" it.
        • A more important near term result would be a cheap Bussard Polywell fusion system.

          A high temperature superconductor that is resistant to high magnetic fields would allow significant efficiency gains and eventually miniaturization.

          Who knows in 40 years every new home might have it's own fusion reactor in the basement because of this material.
    • Re:Another limit? (Score:5, Informative)

      by fyngyrz ( 762201 ) * on Tuesday June 03, 2008 @02:47PM (#23642711) Homepage Journal

      You've reached the wrong conclusion; if it isn't ductile, you can't use it for wires that bend; however, you can certainly use it for wires that follow nonlinear paths.

      • Re: (Score:3, Informative)

        by Chris Burke ( 6130 )
        Right. You won't be running power lines made of ceramics (because of the temperature requirement too) but it's no problem for a fixed installation like a supercomputer.
      • by $RANDOMLUSER ( 804576 ) on Tuesday June 03, 2008 @03:05PM (#23642959)
        Resistance is ductile.
      • by evanbd ( 210358 )
        You mean like how you can't make ceramic [google.com] or glass [wikipedia.org] that's flexible?
      • Re:Another limit? (Score:5, Informative)

        by who knows my name ( 1247824 ) on Tuesday June 03, 2008 @03:17PM (#23643099)
        optical fibres are amorphous, and definitely not ductile. However they are used for miles of cable. You can bend them a few degrees, which is all you really need. I suppose a superconducting ceramic would be worse, but you could still get a significant bend over a kilometre. I think the main barrier is still temperature, I think I read the best we have so far is just above the boiling point of Nitrogen, ~80K
      • Re: (Score:3, Insightful)

        by ceoyoyo ( 59147 )
        That's okay for power lines but it's a real pain for anything that involves a coil. Unfortunately (aside from power lines) coils are involved in the majority of applications that might benefit from superconducting: magnets, motors, etc.

        Even power lines are a pain with ceramics because you can't easily extrude them to make a wire.
        • Why not use stacks of thin layers of superconducting material instead of wires? Since B ~ N and B ~ I (B := generated magnetic field; N := turns of wire; I := current) you can compensate less turns with more current (which shouldnt be a problem since the cross-sectional area of your layer should be slightly larger than that of an equal layer of wires). And since you're using superconducting material, you won't lose energy through eddy currents (but this might generate unwanted noise/stray fields). Or coat y
          • by ceoyoyo ( 59147 )
            It might work, but since superconducting magnets with that design aren't common I suspect there are technical problems. Perhaps the current density has to be too high. Perhaps it's difficult to build stacked plates into a design that provides the right field profile.

            You can't coat wires with ceramic superconductor because it would break when you tried to wind the wire into a coil. Plus the coating would be very thin (compared to the wire) and so you'd run into the current density problem again.
    • Re:Another limit? (Score:4, Informative)

      by mshannon78660 ( 1030880 ) on Tuesday June 03, 2008 @02:50PM (#23642753)
      That's a limitation, rather than a limit. Not being ductile makes it less convenient to use. With magnetism, current density and temperature, the superconductivity disappears as each value reaches a critical point (the limit).
    • Re:Another limit? (Score:5, Informative)

      by JoeBuck ( 7947 ) on Tuesday June 03, 2008 @03:07PM (#23642973) Homepage
      The original superconductors were metals for the most part, but only work at liquid helium temperatures. Then a new class of high-temperature superconductors were discovered, some of which work at liquid nitrogen temperatures; this second class is often called "cuprate superconductors" and they could be described as ceramic. The lack of ductility isn't as bad a problem as the low tolerance for magnetic field that still superconducts at 45 tesla (basically the strongest magnetic field the experimenters could produce).

      Since flowing current creates a magetic field, you can't use cuprate superconductors to carry large currents. Evidently a completely new class of materials has been discovered.

      • Re:Another limit? (Score:5, Informative)

        by caffeinated_bunsen ( 179721 ) on Tuesday June 03, 2008 @03:30PM (#23643285)
        As I understand it, they embed the superconducting material in a soft, non-superconducting metal like silver. There's a proximity effect at boundaries between superconductors and normal metals which allows the superconducting state to extent a short distance into the normal metal -- think of it as the Cooper pairs leaving the superconductor and taking a bit of time to notice that they're in a normal metal and split into single electrons. If the layers of normal metal between the superconducting grains are thin enough, then the supercurrent can run from one grain to the next, through the normal metal, without experiencing resistance.

        The ductility of the metal allows some flexibility and tolerance for thermal expansion, as well as providing a low resistance at high temperatures. That's useful because the ceramic materials have rather high resistance when they're not superconducting, which means that if a small segment of wire warmed up above the transition temperature, its suddenly high resistance and the large current flowing through it would cause it to heat up extremely rapidly. The silver provides a secondary current path, so the wire's likely to heat up slowly enough to turn the power off before the wire melts.
      • Re:Another limit? (Score:4, Interesting)

        by flux pinner ( 1170311 ) on Tuesday June 03, 2008 @04:07PM (#23643791) Homepage

        Since flowing current creates a magetic field, you can't use cuprate superconductors to carry large currents.
        Don't confuse critical fields with critical currents. This paper is talking only about critical fields - it is not trying to describe the amount of current that this material might eventually carry.

        You're right that electric current creates a magnetic field. In a type-II superconductor (like the cuprates and these new FeAs materials), this is managed by introducing defects in the material (grain boundaries, inclusions, etc.) that "pin" the quantitized magnetic flux vortices and prevent them from moving through the material and destroying superconductivity. So it's not fair to say that you CAN'T use cuprates to carry large currents - it's just an engineering problem that has to be dealt with by clever manipulation of the structure of the materials.

        So here's the short version:

        Critical field = intrinsic property of the material.

        Critical current = extrinsic property that depends on critical field, grain structure, presence of second phases, etc.
    • It's perfectly possible to build wires using brittle ceramics, it's just hard work. As I understand it (which may be wrong) wires are made by forming powder in a mold and then melting it. Trouble comes when you think about thermal expansion/contraction. Taking a brittle solenoid from room temperature to 4K or below involves a substantial contraction. Taking it back up to room temperature quickly (quenching a magnet) is probably bad. But it's certainly possible, we have one at work (14T).
    • Re:Another limit? (Score:5, Informative)

      by flux pinner ( 1170311 ) on Tuesday June 03, 2008 @03:56PM (#23643649) Homepage
      There are a variety of techniques (depending on the application) that manufacturers use to overcome the inherent brittle nature of most superconductors.

      For magnet windings, the preferred technique is to fabricate the wire from ductile precursors, draw to final size, wind the coil, and then perform a heat treatment to react the precursors and form the brittle, superconducting phase. This, for example, will be the technique used when brittle Nb3Sn [wikipedia.org] is used in the magnets for the ITER [iter.org] project.

      A related solution is to grind the brittle superconductor into powder, insert it into a tube, and use the natural rolling and sliding action of the particles to draw the material into a fine wire that can be subsequently wound into a magnet, with a heat treatment employed to sinter the powder particles back together to form a continuous superconducting path. This is a common technique for MgB2 [wikipedia.org] superconductors.

      For non-magnet applications (like power transmission), the preferred technique is to make a tape (e.g. YBCO [wikipedia.org]) that has only a very thin layer of brittle superconductor. Just like a glass fiber, this very thin layer has a very small bending moment in one direction, and so can be spooled (and unspooled) in this direction, allowing you to manage long lengths.
    • Re: (Score:2, Informative)

      by Anonymous Coward
      I worked in a group at Argonne Natl. Lab that formed wire out of the cuprate materials. We had magnetic coils, high current transmission bars, etc. All were ceramic and brittle but usable. The were formed by slowly burning the binder out of green forms that would later sinter into a solid product.

      The issues that restricted further development was critical current density, which would limit the amount of current and the strength of the magnetic field.
  • Interesting... (Score:4, Insightful)

    by misterpmosh ( 1301415 ) on Tuesday June 03, 2008 @03:09PM (#23643011)
    That's truly fascinating if they can tolerate such a large magnetic field. While we may rarely need to tolerate 45 tesla magnetic fields in practice, the physics behind this must be new to our experience. Unexplained experimental results always spark interesting theoretical work, possibly leading to more practical materials.

    Scanning the paper, it seemed to have little bearing on this magnetic field tolerance, but rather talked about the effects of grain boundaries. Did anyone understand how the paper related to the press release?

  • AC! (Score:2, Funny)

    by tcoder70 ( 1051640 )
    "Ah Crappp!!!" - Magneto, 2008
  • by caffeinated_bunsen ( 179721 ) on Tuesday June 03, 2008 @03:16PM (#23643091)
    Read that preprint, or at least look at the pictures -- specifically Fig. 6. It's a measurement of the upper critical field (i.e. the magnetic field that destroys the superconducting state) versus temperature. The 90% line (where the resistivity is 90% of its normal-state value) does indeed go off the graph at low temperatures; it extrapolates to about 60 T for 5 K.

    There's a big difference between "This material has a very high critical field" (which is what the article said) and "This material has no critical field" (which is what the summary said).
    • by hardburn ( 141468 ) <hardburn@wumpu s - c a v e.net> on Tuesday June 03, 2008 @03:25PM (#23643209)

      If you have a 60T magnet laying around, please get in touch. I have an evil plan that needs hatching.

    • by PIPBoy3000 ( 619296 ) on Tuesday June 03, 2008 @03:44PM (#23643483)
      I was looking at the magnetic flux density table [wikipedia.org] and found a few interesting tidbits:
      • 1.5 T is what's used in MRIs (people have died when metallic objects fly around in these fields)
      • 16 T will levitate a frog
      • 45 T is the strongest magetic field continuously produced in a laboratory.
      • 10,000 T is instantly lethal to organic life
      Basically we're fine levitating frogs, but probably won't be able to use it as part of an instant-death ray.
      • hmm, that last number is intriguing, according to the same article no one has ever seen more than 2800 T. Makes you wonder how they determined that 10 kT are lethal.
        • Re: (Score:2, Interesting)

          by MiniMike ( 234881 )
          Maybe they estimated that a field of that strength will separate H20 or some other molecule that life finds necessary? Just a random guess.

          Too bad that the strongest field produced is only 2800T (actually strongest continuous is only 45T), since it only takes 16T to levitate a frog then 100kT would probably launch it (or remaining portions) into space...
          • Maybe they estimated that a field of that strength will separate H20 or some other molecule that life finds necessary? Just a random guess.

            Not too far off. In the thread earlier today about the magnetar, in which this same topic came up, it was said that the fatal effect would be because of the diamagnetism of water. Given that we're all mostly water, then once that stuff becomes magnetised in bulk a 100,000T field would shred any living thing on earth instantly.

      • Re: (Score:2, Informative)

        by xorbe ( 249648 )
        10^5 is 100,000 T (instantly lethal to organic life)
      • by dargaud ( 518470 )

        100,000 T is instantly lethal to organic life
        (corrected). What is it that makes a strong magnetic field lethal ? Some molecules separate ? Differential motion of diamagnetic / ferromagnetic body components ? Other ? I'm just surprised it happens at such incredibly strong intensities.
  • by seanonymous ( 964897 ) on Tuesday June 03, 2008 @03:22PM (#23643161)
    That's really neat and all, but please let me know when they find something that's immune to gravity, as it's essential to a project I'm working on. (I have a deadline.)
    • by CowboyNealOption ( 1262194 ) on Tuesday June 03, 2008 @03:29PM (#23643269) Journal
      Sadly everything on the planet that was immune to gravity drifted away from the earth before people existed.
    • by ceoyoyo ( 59147 ) on Tuesday June 03, 2008 @03:36PM (#23643359)
      It's been known for quite a while. It's called vacuum. There's LOTS of it around too.
      • Yes I know it's a joke, but for anyone confused: the effects of gravity are quite independent of vacuum/atmosphere. The astronauts on the ISS aren't weightless because there is no air or gravity. At 211 miles up they experience about 88% of the strength of Earth's gravitational field that we do on the surface. They are weightless because they are in free fall - much like you can achieve weightlessness on a carnival ride or a plane moving the right way.
        • by ceoyoyo ( 59147 )
          It's bad enough you tried to explain the joke, but you explained the wrong thing!

          Since gravity affects everything, matter or energy, the only thing "immune" to gravity is nothing: vacuum. Of course it has to be true vacuum, without even any energy in it, which may or may not exist.
      • Re: (Score:3, Funny)

        It might not be as plentiful as you think. I've heard an anecdote that the Guinness Book of World Records lists vacuum as the most expensive substance known to man...

        Most expensive by weight, that is. Additionally, higher quality vacuums are exponentially more expensive!

      • by dargaud ( 518470 )
        Hmmm, I'm not even quite sure about that. Since vacuum contains virtual particles, which have a mass, I'm pretty sure you can compute the mass density of a block of vacuum. I'm not quite up to date on my quantum mechanics (although I implement it in software !) to give you a number.
    • Re: (Score:3, Funny)

      by 12357bd ( 686909 )

      Did you ever heard about something involving two cats?

      The only detected problem was the noise...

  • by flux pinner ( 1170311 ) on Tuesday June 03, 2008 @03:24PM (#23643199) Homepage
    Ack - looks like caffeinated_bunsen beat me to the punch. But it bears repeating - this paper certainly says nothing like "this superconductor is immune to magnetism". This material has a very high critical magnetic field, and if they figure out how to improve the connectivity then it might even someday be able to carry a current density of engineering significance. But it certainly is not "immune" to magnetism in any qualitatively different way than any other type-II superconductor out there. Still...it's nice to see that high-temperature superconductivity can be observed outside the cuprate family, and this paper (showing that it also has a high critical magnetic field) should spur some serious R&D work outside the theoretical physics community.
  • reality check (Score:5, Informative)

    by Anonymous Coward on Tuesday June 03, 2008 @03:28PM (#23643241)
    I am a condensed-matter physicist but not a superconductor specialist.

    The article does not say that the material is immune to magnetism.

    The data relevant to this discussion is presented in Fig. 6 in the paper, which is a plot of the upper critical field (the maximum field the material can support and still be superconducting) versus temperature. Look at the traces marked with square markers.

    Notice that these curves do not diverge to infinity as the summary would have you believe.

    Granted, values in the 50's of Tesla seem pretty big, considering that the ambient magnetic field on Earth is about 0.5 Tesla. But note that other superconductors have critical fields in this same range. The famous high-Tc superconductor YBCO has a critical field of 135 Tesla (ref: http://www.springerlink.com/content/j0128jt30843362u/)

    Compared to elemental superconductors, whose critical fields are around 1 Tesla or less, this material does indeed support a lot more magnetic field. But it certainly isn't "immune to magnetism"
    • Re:reality check (Score:5, Informative)

      by necama ( 10131 ) on Tuesday June 03, 2008 @03:55PM (#23643639)

      Granted, values in the 50's of Tesla seem pretty big, considering that the ambient magnetic field on Earth is about 0.5 Tesla.
      I'm just quibbling on units -- the Earth's magnetic field is 0.5 gauss, or, 50 microTesla. Other than that, I agree with your comment 100%.

      --

      Just another condensed matter physicist.
    • by Vario ( 120611 )
      I am not a specialist for superconducting materials either but I think they think that the material is something like a type 1 superconductor with a very high critical field Bc.

      The material can only be of type 1; that means complete expulsion of magnetic flux, if the samples are single crystalline. Their actual measurements show a high critical field Bc2 for polycrystalline samples.

      So it is not "immune to magnetism", which can hardly be the case for superconductors but might allow AC current transport witho
  • ... "New Supercomputer Found 'Immune To Magnetism'", and for a moment I was wondering how something like that was engineered.

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