A Step Towards Proving the Riemann Hypothesis 133
arbitraryaardvark writes "A new mathematical object has been discovered by Bristol University student Ce Bian. The Riemann hypothesis, unproven since 1859, has to do with the distribution of primes and something called L-functions. Bian has demonstrated the first known third-degree transcendental L-function. This apparently opens up a new way to go about looking for proofs of the Riemann hypothesis. There is an unclaimed $1 million prize for a valid proof. We've discussed a couple of earlier attempts to claim the prize."
I see a future of (Score:2)
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You miss the point (Score:5, Informative)
The solution isn't to be found through massive computing effort. They are looking for a proof, not a computation. They need creativity, not horsepower.
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> theoretical advances
That 10,000 hours of computer time will be available from a wristwatch in two or three years. The key ingredient here is theory, creativity, etc.
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I, for one, welcome our new HP-01 [hpmuseum.org] overlords.
My own personal proof (Score:5, Funny)
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...as we all know a grue can't resist the tasty flesh of a non-trivial zero.
True enough. The interesting nature of non-trivial solutions is apparent to all; grue and non-grue alike.
I posit that the only way to prove the hypothesis is to kill a grue and vivisect it...
But not in that order! "Vivisection" means dissection while alive. You'd need to capture a live and viable grue and then not kill it until (too early in the) dissection.
So until someone is brave enough to fight a grue and extract the flesh of the non-trivial zero, that million dollars is going unclaimed.
Mathematicians are known to go adventuring from time to time, but mostly they seem to prefer coffee or tea for the extraction of proofs from the darkness.
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HOUSED.
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Like when you try to eat a kilowatt of yellow.
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I wonder... (Score:1)
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I have already solved this! (Score:4, Funny)
enough room in the margin of this
text area to display it properly.
Re:I have already solved this! (Score:5, Funny)
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Re:I have already solved this! (Score:5, Interesting)
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Why is x^2+y^2=z^2?
I mean, I know the geometric explanation - the area of a square of side Z for any right-angled triangle, where Z is the hypotenuse is the area of the sum of squares of the other sides.
What I want to know is, fundamentally, why? I've got this feeling the geometric approach is actually a side effect of the way that orthogonal axes relate to one another.
Same thing with expanding it to 3 dime
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Although I still have yet to see anything that explains why the sum of the areas trick for pythagoras should work in a theoretical manner, that actually explains the underlying principles without resorting to a geometric argument. Which is kind of cheating - what I want to know is why the geometry works that way
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The Riemann Hypothesis, by Robert Ludlum (Score:5, Funny)
Cue the creepy, hushed voice-over:
In a University in Lower Saxony, a mathematician had formulated a remarkable conjecture. Its effects would be felt worldwide.
The Riemann Hypothesis, by Robert Ludlum. Now in paperback.
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rj
smile and nod (Score:5, Funny)
Re:smile and nod (Score:5, Funny)
I got through half a year of classes on game-theory in Korean with it. The professor never noticed I didn't speak a word Korean. Tests were in English, and the guy just kept asking ending in '...isn't that right, studentX?' or '...do you not agree, studentY?'.
Smile and nod baby, smile and nod. Best followed by a short single chuckle, as if the intrinsical irony of reality does not elude you.
By the end of the semester the guy actually seemed to like me.
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The "effort trying to fake it" somehow always ends up with me learning something...
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This actually happened, and I turned out looking quite smart, even though I had no idea what the whole point of the calculation was. To be honest though, I went home and read it through afterwards.
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Strictly speaking, that's the rank rather than the dimensionality of the matrix (it is, however, the geometric dimensionality of the manifold in which it lies), but if the matrix is invertible (full-rank), they're the same thing.
I'd agree with the other poster, actually - go for topology if you want to test the bounds of your intuition. I found it to be one of the most intuitive fields of higher mathematics I gained exposure to, despite the fact that I generally consider myself firmly in the symbolic camp
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Agree. I'm the guy who submitted the article, and I have no idea what it's about.
It just felt slashdotty.
Similar Sounding (Score:1)
Nevermind. Thought it said "Rainman" (Score:1, Funny)
Did you fart, Ray? Did you fucking fart?
What's really going on here (Score:5, Informative)
Booker and Ce Bian constructed certain degree 3 L-functions, but it is best to think of their discovery as follows: there is a complicated 5-dimensional membrane known to mathematicians as "SL(3,Z)\SL(3,R)/SO(3)". This membrane has subtle number-theoretic symmetries, so that its modes of vibration encode number-theoretic information. These modes (and their vibrational frequencies) are being extensively studied, but they are very transcendental objects so they cannot be written down explicitely and must be computed numerically. While certain modes (and frequencies) were already known numerically (they can be constructed from vibrational modes of the 2-dimensional membrane "SL(2,Z)\SL(2,R)/SO(2)" via something known as the Gelbart-Jacuqet lift) we now have the the first numerical computation of "native" modes of the 5-dimensional membrane -- those that aren't related to lower-dimensional cases. To each such mode of vibration there is an associated "L-function (similar to the Riemann zeta function), and it is the L-functions that were constructed. In fact, verifying that the approximate L-functions that were found correspond to actual modes of vibration is not easy (in the 2-dimensional case there is important work of Booker with others about this).
In short, this is an important advance in automorphic forms, but it is so technical that it doesn't belong on SlashDot.
It is important to realize that while indeed there is a ("Generalized") Riemann Hypothesis associated to these L-functions, numerically computing them represents zero progress toward proving the Riemann hypothesis for these L-functions or the original Hypothesis for the Riemann zeta function. At most this will allow very approximately computing some of their zeros and thus a weak check on the GRH for these L-functions.
Re:What's really going on here (Score:5, Funny)
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1. Riemann: I hypothesise that this is true.
2. Computer: Looks good, but this isn't proof.
3. Scientist: If I assume that the Riemann hypothesis is true, we can deduct X, Y, Z etc.
4. ???
5. Engineer: I've found a practical application for Z.
6. Theoretician: Yes, but it's not proven
Re:What's really going on here (Score:5, Interesting)
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Does it mean we are closing to the Goedel's incompleteness levels of the development of formal number theory?
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"Solving this problem will contribute to (find|build|formulate) what?"
I know near zero of Mathmatics, so I'm curious about ( And Wikipedia is not helping, though... ).
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I don't know if somebody asked this before: "writing Hamlet contributed to find|build|formulate what?" ?
Seriously, numerically computing "automorphic forms" (whatever they are) contributes to understanding these objects, for example for formulating conjectures about them and for testing known conjectures. This is good for analytic number theory, but at the moment has few applications outside mathematics. Doing mathematics is important because it is a triumph of human intellect, not because it has any pr
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Re:What's really going on here (Score:4, Informative)
And he didn't solve the continuum hypothesis. He showed that you cannot prove CH from the ZF axioms. Gödel had previously show that you cannot *disprove* CH from ZF (unless ZF is inconsistent). Together these results show that CH is independent of ZF.
So CH is still an unresolved problem today. As far as anyone knows, either CH or its negation can be taken as a separate axiom of itself, which leaves it an open question.
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Case in point: One set theorist (Woodin) published a paper just a few years ago putting forth an argument based on "omega logic" (which I don't claim to understand) that C = Aleph-2 (and therefore CH is false), while a colleague of his (Foreman) countered with an argument based on "generalized large cardinals" (which I don't claim to understand) that CH is true. So no, it isn't resolved at all.
The idea is to find a new axiom that is s
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In short, this is an important advance in automorphic forms, but it is so technical that it doesn't belong on SlashDot.
In my extremely limited experience, I have noticed that brilliance is often reflected by the ability to simply explain a complex idea. One of the interesting benefits of Slashdot is that often there is someone reading who either has seen a brilliant reduction of a complex problem to a simple explanation, or alternatively has sufficient experience in the area to reduce it to a simple concept. YMMV. :)
Vibrating membranes? (Score:2)
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So, my question is: what does this MEAN? Are we closer to faster than light travel, anti-gravity hover-crafts, cold fusion, teleporters, a better burning light bulb, that 2+3 really does equal 5 (yeah, I least I got the prime number part), What?
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You do not really understand something unless you can explain it to your grandmother. -- A. Einstein.
Lucky for us, my grandma doesn't read slashdot. But in a long-ago life, I earned a minor degree in math and took much more math en route to a degree in physics (undergrad and grad... but nowhere near this Riemann space stuff). So, I am both curious and competent. And I regret to say you d
Re:What's really going on here (Score:5, Informative)
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I am pretty sure this is a first.
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Re:What's really going on here (Score:4, Interesting)
I already know a few things about L-functions and GRH, but I'm not sure what the "membranes" you refer to are. Are you speaking of the same "membranes" that appear in M-theory?
Please STOP reading Science Daily! (Score:1, Informative)
The Holy Roman Empire, is NOT holy, nor Roman.
Is Slashdot a slash and a dot?
Riemann zeta function on Wikipedia (Score:2, Funny)
Fascinating!
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So why do you watch it?
Seriously.
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Just simplify it (Score:1)
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You're thinking of physicists, who can prove this hypothesis for all prime numbers which are perfectly spherical and exist in a perfect vacuum.
where's ....... (Score:1)
Unproven since 1859??? (Score:3, Funny)
question (Score:3, Interesting)
zeta(s)=sum(n=1, inf)(1*n^-s)
Dirichle L-function is defined as
L(f, s)=sum(n=1, inf)(f(n)*n^-s)
so when f(n)=1, Dirichle L-function becomes Riemann zeta function.
L-function is just another representation (called Euler product) of Dirichle L-function.
L(f, s)=prod(prime p=1, inf) P(p, s)
where
P(p,s)= 1 + f(p)p^-s + f(p^2)p^-2s +
The Euler product I figured must work similar to the usual prime number decomposition: you got the sum of 1's and you got a product of primes.
That is how far I got.
Now what the heck are degrees of those L-functions?
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Fahrenheit?
Re:question (Score:4, Informative)
This is where things get technical. The Riemann Zeta-function $\zeta(s) = \sum_n n^{-s}$ has the Euler product representation $\zeta(s) = \prod_p \left( 1 - p^{-s}\right)^{-1}$. Similarly, the Dirichlet L-functions $L(s;\chi) = \sum_n \chi(n)/(n^s)$ have the Euler product $\prod_p L_p(s;\chi)$ with $L_p(s;\chi) = 1/( 1 - \chi(p)/(p^s))$. In both cases, the factor at each prime $p$ takes the form $1 / ( 1 - a(p)/p^s )$, for some number $a(p)$ depending on $p$. We think of this factor as a the inverse of a polynomial of degree 1 in the variable $p^(-s)$ (the polynomial is $P(T) = 1 - aT$).
Similarly, to GL(3) Hecke-Maass forms such as the ones computed by Booker and Ce Bian, there is an attached L-function $L(s;f)$ which can be represented as an Euler product, $\prod_p L_p(s;f)$. This time, however, the local factors $L_p(s;f)$ are the inverses of cubic polynomials, that is $1/L_p(s;f)$ takes the form $P(p^-s)$ where $P(T) = 1 - aT - bT^2 - cT^3$ for some coefficients $a,b,c$ depending on $p$ (and on $f$, of course). This is why we call it an L-function (or Euler product) of degree 3.
Using the Fundamental Theorem of Algebra, it is common to factor the polynomial $P(T)$, and write it in the form $\prod_{j=1}^{3} ( 1 - \alpha_j(p) T)$. Thus an Euler product of degree $d$ takes the form:
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Do we really want this to happen? (Score:2)
Am I the only one... (Score:1)
Those were the days (Score:3, Funny)
...before 1859, when cars were pulled by horses and the Riemann hypothesis was still not unproven. Those were they days, I tell you, those they were.
I forgot to credit Marginal Revolutions blog (Score:5, Informative)
http://www.marginalrevolution.com/marginalrevolution/2008/03/assorted-link-4.html [marginalrevolution.com]
http://www.marginalrevolution.com/ [marginalrevolution.com]
Sage and L-functions (Score:3, Interesting)
Obligatory lexx reference (Score:2)
Practical benefits? (Score:2)
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Ce Bian and Andrew Booker (and their computer) should at least win SOME prize and may need to practice their Sweedish.....
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Ce Bian and Andrew Booker (and their computer) should at least win SOME prize and may need to practice their Sweedish.....
They might win some prize, but certainly not one that would involve any Swedish.
There is no Nobel prize for mathematics. The Fields medal is the closest equivalent.
Re:wow... (Score:4, Informative)
Do you know what you're talking about? (Score:5, Informative)
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