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Math Science

A Step Towards Proving the Riemann Hypothesis 133

arbitraryaardvark writes "A new mathematical object has been discovered by Bristol University student Ce Bian. The Riemann hypothesis, unproven since 1859, has to do with the distribution of primes and something called L-functions. Bian has demonstrated the first known third-degree transcendental L-function. This apparently opens up a new way to go about looking for proofs of the Riemann hypothesis. There is an unclaimed $1 million prize for a valid proof. We've discussed a couple of earlier attempts to claim the prize."
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A Step Towards Proving the Riemann Hypothesis

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  • Reimann botnets infiltrating hundreds of thousands of computers to work on the solution. Unfortunately, Comcast finds out and starts throttling their internet bandwidth. Math is set back 100 years.
  • by explosivejared ( 1186049 ) <hagan.jared@NOsPaM.gmail.com> on Thursday March 20, 2008 @02:07PM (#22810104)
    Non-trivial zeroes of the zeta function are 1/2 because they naturally form as wholes, but as we all know a grue can't resist the tasty flesh of a non-trivial zero. I posit that the only way to prove the hypothesis is to kill a grue and vivisect it to search for the other half of the non-trivial zero. So until someone is brave enough to fight a grue and extract the flesh of the non-trivial zero, that million dollars is going unclaimed.
    • Re: (Score:3, Funny)

      by Anonymous Coward

      ...as we all know a grue can't resist the tasty flesh of a non-trivial zero.

      True enough. The interesting nature of non-trivial solutions is apparent to all; grue and non-grue alike.

      I posit that the only way to prove the hypothesis is to kill a grue and vivisect it...

      But not in that order! "Vivisection" means dissection while alive. You'd need to capture a live and viable grue and then not kill it until (too early in the) dissection.

      So until someone is brave enough to fight a grue and extract the flesh of the non-trivial zero, that million dollars is going unclaimed.

      Mathematicians are known to go adventuring from time to time, but mostly they seem to prefer coffee or tea for the extraction of proofs from the darkness.

    • Re: (Score:2, Funny)

      by Anonymous Coward
      As we all know, attempting to vivisect a grue after its untimely demise will only result in self-inflicted vocabular impugnation.
    • Do I get to use my flashlight?
    • As vivisection requires that the entity being dissected be alive at the time of dissection, hence the very definition of the word vivisection. You can't kill the grue then dissect it, you must capture it alive then find a way to secure it so you can vivisect it. My guess would be that the grue wouldn't like being vivisected and as a result the search for the non-trivial zero will involve the division of blood and flesh of the searcher, possibly by an amount of blood and flesh such that you end up with an i
  • If all the theorems/lemmas/etc used in the ultimate proof were each given an even share of the $1M, and we followed things back recursively, how much money would each person get.
  • by Anonymous Coward on Thursday March 20, 2008 @02:13PM (#22810174)
    ...But unfortunately I do not have
    enough room in the margin of this
    text area to display it properly.
    • by popmaker ( 570147 ) on Thursday March 20, 2008 @02:38PM (#22810568)
      am on ship on way to england stop have solved riemann hypothesis stop will give details on return stop
    • by 00_NOP ( 559413 )
      I wonder if Fermat really did have a proof. Thoughts?
      • by SpecTheIntro ( 951219 ) <<moc.liamg> <ta> <ortniehtceps>> on Thursday March 20, 2008 @03:18PM (#22811194)
        You know, there's a lot of speculation about that. I suspect he did have a proof, but I'm skeptical that it was correct. There's no doubt that the man was brilliant but we've had people working on that question ever since Fermat died and no one has been able to produce a "simple, elegant" proof. (Fermat's own description, there.) But there's plenty of precedent for mathematicians making things inordinately complex before some young genius comes along and shows a magnificently simple way of achieving the same thing.
        • I've got this odd hunch that the original solution for Fermat's last theorem is related to Pythagoras.

          Why is x^2+y^2=z^2?

          I mean, I know the geometric explanation - the area of a square of side Z for any right-angled triangle, where Z is the hypotenuse is the area of the sum of squares of the other sides.

          What I want to know is, fundamentally, why? I've got this feeling the geometric approach is actually a side effect of the way that orthogonal axes relate to one another.

          Same thing with expanding it to 3 dime
          • There are about a million people including you who thought that because the equation of Fermat's last theorem looked simple, there was some simple reason why it was true. (Don't worry because this list includes a lot of good mathematicians, including maybe Fermat himself) Some of these people would try and turn the 'feeling' you expressed above into something that looked like a mathematical proof, and then send it to various mathematicians, university departments etc. In fact the department that was respons
            • Which is why I've never tried sending out a proof... it's not baked yet - it's just a hunch.

              Although I still have yet to see anything that explains why the sum of the areas trick for pythagoras should work in a theoretical manner, that actually explains the underlying principles without resorting to a geometric argument. Which is kind of cheating - what I want to know is why the geometry works that way :)
      • Re: (Score:3, Informative)

        by Kjella ( 173770 )
        I've long since forgotten the details, but there is a "proof" along the lines of his previous proofs that is simple, elegant and wrong. Most likely that was his proof and when he realized the flaws he never published it, so all that's left is an overly excited comment in a margin. Of course, that's an incredibly boring and everyday explaination, so it's usually discarded in favor of mystery and legend.
    • phew... another lawyer.
  • by HiggsBison ( 678319 ) on Thursday March 20, 2008 @02:19PM (#22810272)

    Cue the creepy, hushed voice-over:

    In a University in Lower Saxony, a mathematician had formulated a remarkable conjecture. Its effects would be felt worldwide.

    The Riemann Hypothesis, by Robert Ludlum. Now in paperback.

  • by esocid ( 946821 ) on Thursday March 20, 2008 @02:22PM (#22810338) Journal
    (just smile and nod, smile and nod. they'll never know you have no idea what this means)
    • by piemcfly ( 1232770 ) on Thursday March 20, 2008 @02:52PM (#22810802)
      I can vouch for the smile-nod method.

      I got through half a year of classes on game-theory in Korean with it. The professor never noticed I didn't speak a word Korean. Tests were in English, and the guy just kept asking ending in '...isn't that right, studentX?' or '...do you not agree, studentY?'.

      Smile and nod baby, smile and nod. Best followed by a short single chuckle, as if the intrinsical irony of reality does not elude you.

      By the end of the semester the guy actually seemed to like me.
      • Hey, and have ONE thing that you look for to see if it's wrong. Constantly. Like dividing by zero. Odds are, it IS going to happen, as a mistake, at least once during a semester, and THAT is your moment to shine, baby! Even if you have NO idea what is going on, you DID notice that the lecturer tried to divide by zero - so raise your hand and gain instant respect by everyone in the room - which usually people which are themselves busy applying the smile and nod method, have no idea what's going on, but did n
        • In the end, you're only fooling yourself. Better to learn the material for real than waste effort trying to fake it.
          • Re: (Score:3, Interesting)

            by popmaker ( 570147 )
            Yes, indeed. But of course I was joking. Also: This way of "fooling myself" usually maeks me go home and read the book for real, just to know what the hell I was talking about. :)

            The "effort trying to fake it" somehow always ends up with me learning something...
        • I've never seen a lecturer try to divide by zero in 5+ years of math classes. There are a few errors that come up quite frequently, but lecturers usually know in advance what they're going to demonstrate on the board. Dividing by zero would mean that you had really gone wrong somewhere, and in fact the real error would probably be that you had put the wrong expression on the bottom of a fraction (one that happened to be equal to zero).
          • Well, it could happen that the nominator was zero also and he just thought that it was enough for the whole expression to be zero and forgot to check the denominator. That could have been okay if it just so happened that the fraction had zero as a limit, not a value, in that point.

            This actually happened, and I turned out looking quite smart, even though I had no idea what the whole point of the calculation was. To be honest though, I went home and read it through afterwards.
            • i had a professor who didn't mind that you couldn't divide non-zero numbers by zero, but was quite annoyed that he wasn't allowed to divide zero by zero. i never asked him what he thought the value of 0/0 was supposed to be..
    • by l2718 ( 514756 )
      Actually, we can tell quite easily -- but sometime we get so excited we rudely keep trying to explain anyway. In any case, you are right that because it is so technical, this story doesn't belong on this forum.
    • Re: (Score:3, Interesting)

      (just smile and nod, smile and nod. they'll never know you have no idea what this means)
      Agree. I'm the guy who submitted the article, and I have no idea what it's about.
      It just felt slashdotty.
  • Not to be confused with the Hymen Riepothesis.
  • Uh oh... Uh oh fart.

    Did you fart, Ray? Did you fucking fart?

  • by l2718 ( 514756 ) on Thursday March 20, 2008 @02:29PM (#22810436)

    Booker and Ce Bian constructed certain degree 3 L-functions, but it is best to think of their discovery as follows: there is a complicated 5-dimensional membrane known to mathematicians as "SL(3,Z)\SL(3,R)/SO(3)". This membrane has subtle number-theoretic symmetries, so that its modes of vibration encode number-theoretic information. These modes (and their vibrational frequencies) are being extensively studied, but they are very transcendental objects so they cannot be written down explicitely and must be computed numerically. While certain modes (and frequencies) were already known numerically (they can be constructed from vibrational modes of the 2-dimensional membrane "SL(2,Z)\SL(2,R)/SO(2)" via something known as the Gelbart-Jacuqet lift) we now have the the first numerical computation of "native" modes of the 5-dimensional membrane -- those that aren't related to lower-dimensional cases. To each such mode of vibration there is an associated "L-function (similar to the Riemann zeta function), and it is the L-functions that were constructed. In fact, verifying that the approximate L-functions that were found correspond to actual modes of vibration is not easy (in the 2-dimensional case there is important work of Booker with others about this).

    In short, this is an important advance in automorphic forms, but it is so technical that it doesn't belong on SlashDot.

    It is important to realize that while indeed there is a ("Generalized") Riemann Hypothesis associated to these L-functions, numerically computing them represents zero progress toward proving the Riemann hypothesis for these L-functions or the original Hypothesis for the Riemann zeta function. At most this will allow very approximately computing some of their zeros and thus a weak check on the GRH for these L-functions.

    • by kalirion ( 728907 ) on Thursday March 20, 2008 @02:35PM (#22810518)
      Wow, it's so clear now!
      • by Kjella ( 173770 )
        "Math" could very well be considered its own language, and without understanding the words or the grammar explaining something becomes exceedingly hard. At any rate, I've found assumption to give 99% of the real-world value anyway:

        1. Riemann: I hypothesise that this is true.
        2. Computer: Looks good, but this isn't proof.
        3. Scientist: If I assume that the Riemann hypothesis is true, we can deduct X, Y, Z etc.
        4. ???
        5. Engineer: I've found a practical application for Z.
        6. Theoretician: Yes, but it's not proven
        • by bjorniac ( 836863 ) on Thursday March 20, 2008 @04:45PM (#22812352)
          Somewhat, but the parallel conjecture that went all the way back to Euclid couldn't be proven, even though it seemed largely true. Eventually Riemannian geometry arose as something that broke this well established conjecture. Often, yes, it's useful to assume conjectures, but don't underestimate the value of a proof, or even the value of failed proofs.
    • Re: (Score:3, Informative)

      by MaWeiTao ( 908546 )
      I sincerely tried to follow all that, but it's so far over my head that it's in orbit around Jupiter.
    • *smiles and nods*
    • Re: (Score:3, Interesting)

      by mapkinase ( 958129 )
      Everybody have already noticed that most recent proofs of outstanding hardcore die hard theorems are mind-bogglingly long or simply numeric (it's not a proof, I know).

      Does it mean we are closing to the Goedel's incompleteness levels of the development of formal number theory?
    • I don't know if somebody asked this before:

      "Solving this problem will contribute to (find|build|formulate) what?"

      I know near zero of Mathmatics, so I'm curious about ( And Wikipedia is not helping, though... ).
      • by l2718 ( 514756 )

        I don't know if somebody asked this before: "writing Hamlet contributed to find|build|formulate what?" ?

        Seriously, numerically computing "automorphic forms" (whatever they are) contributes to understanding these objects, for example for formulating conjectures about them and for testing known conjectures. This is good for analytic number theory, but at the moment has few applications outside mathematics. Doing mathematics is important because it is a triumph of human intellect, not because it has any pr

    • by debrain ( 29228 )

      In short, this is an important advance in automorphic forms, but it is so technical that it doesn't belong on SlashDot.

      In my extremely limited experience, I have noticed that brilliance is often reflected by the ability to simply explain a complex idea. One of the interesting benefits of Slashdot is that often there is someone reading who either has seen a brilliant reduction of a complex problem to a simple explanation, or alternatively has sufficient experience in the area to reduce it to a simple concept. YMMV. :)

    • What's all this about vibrating membranes? I thought this was supposed to be about math!
    • Nice explanation.
    • Gelbart-Jacuqet
      Gelbart-Jacquet?
    • Regrettably, I chose the road more traveled so have no idea what this means. Looked up "automorphic forms"... yeah, that didn't help.

      So, my question is: what does this MEAN? Are we closer to faster than light travel, anti-gravity hover-crafts, cold fusion, teleporters, a better burning light bulb, that 2+3 really does equal 5 (yeah, I least I got the prime number part), What?

    • Re: (Score:3, Insightful)

      by ediron2 ( 246908 ) *

      In short, this is an important advance in automorphic forms, but it is so technical that it doesn't belong on SlashDot.

      You do not really understand something unless you can explain it to your grandmother. -- A. Einstein.

      Lucky for us, my grandma doesn't read slashdot. But in a long-ago life, I earned a minor degree in math and took much more math en route to a degree in physics (undergrad and grad... but nowhere near this Riemann space stuff). So, I am both curious and competent. And I regret to say you d

      • by l2718 ( 514756 ) on Thursday March 20, 2008 @08:55PM (#22814632)
        Let's try:
        • The "membranes", "modes" and "frequencies" here are already a physical analogy. Number theorists study objects (``automorphic forms'' -- no matter why they are called this way) that live on some ``manifolds'' (no matter what that means, either). But to get some intuition you can replace ''manifold'' with ''taut membrane'' (like a drum) and ''automorphic form'' with ''normal mode'' a.k.a. basic ''standing wave'', as you call it. An important problem in mathematical physics is to find what are the possible frequencies of standing waves on a particular surface. The problem here is analogous.
        • To see a picture of the 2-dim membrane I was talking about, see here [springer.de]. Start by taking a half-infinite strip of width 1, and cut off a semi-circular bit at the bottom like in the picture (the strip extends infinitely far at the top. Next, glue the two infinite sides together so the strip becomes a cylinder. Finally (that's not in the picture) imagine that as you go further and further up the cylinder, its radius becomes smaller and smaller, so the real thing is a kind of infinite funnel.
        • To see what a standing wave on this membrane looks like, see here [umn.edu] (this was computed numerically by Dennis Hejhal).
        • The "lift" that takes a standing wave on this space to a standing wave on the 5-dim space is really complicated (and is a very indirect construction). There just isn't a non-technical way to describe it.
        • However, we know what the "lift" does to the frequencies: if you start with a standing wave you found numerically, and approximately know its frequency, then you know there will be a lifted guy of a calculatable frequency on the 5-dim space. So the interesting problem is to find standing waves with frequencies which are different from the ones we already know about (because we have calculated a lot of standing waves on the 2-dim surface).
        • One symmetry this infinite funnel has is left-right reflection (it is apparent both in the picture of the strip and in the picture of the vibrational mode). The other symmetries are difficult to describe in a blog post. What's important is that the modes of vibration must respect the symmetries.
        • It is true that to each such ''standing wave'' (on the 2-dim surface, on the 5-dim space, and on others) there is an associated L-function. The Riemann Hypothesis for these L-function (the same formulation: all zeros are on the critical line) is called the "Generalized (or Grand) Riemann Hypothesis" or GRH.
        • It was possible to calculate a few zeros of the newly-found modes, and see that indeed they are where they are supposed to be. This gives some evidence for the GRH. Calculations like this can always falsify the GRH (by finding a zero off the line). However, these calculations don't represent any progress toward proving the GRH -- that was confusion on part of the person who submitted the story to slashdot.
        I hope this helps.

    • ...but it is so technical that it doesn't belong on SlashDot.

      I am pretty sure this is a first.

      • I feel a disturbance in the Force, as if a million quantum-physicists on slashdot cried out in agreement and were suddenly silenced...
    • by Metasquares ( 555685 ) <slashdot AT metasquared DOT com> on Thursday March 20, 2008 @07:15PM (#22813922) Homepage
      Quite the contrary, actually - I think we need more discussions (and more posts) like this on Slashdot. It's a good starting point to look things up.

      I already know a few things about L-functions and GRH, but I'm not sure what the "membranes" you refer to are. Are you speaking of the same "membranes" that appear in M-theory?
  • Science Daily is NOT science, nor Daily.
    The Holy Roman Empire, is NOT holy, nor Roman.

    Is Slashdot a slash and a dot?
  • The popular T.V. Show NUMB3RS had an episode ("Prime Suspect") in which criminals kidnapped a child and demanded as ransom a possible proof of the Riemann Hypothesis from a mathematician. The proof would be used to steal interest rates from an encrypted website.

    Fascinating!
    • Re: (Score:3, Funny)

      by Surt ( 22457 )
      That show is the best mathy/sciency show on television, mostly because they never, ever get the science wrong. Also, there's some good acting.
      • Re: (Score:2, Informative)

        by amorri09 ( 1134951 )
        Wow, how wrong are you.....I honestly think that Numb3rs is the most contrived POS on TV. First off, The acting ISN'T good. Second, The plots are always work back kind of solutions packed with the mathmatical equivelant to the techno-babel you see on most network Sci-fi tv shows (eg. Hey! I was just reading about this thing called the Riemann Zeta something, lets make it into an episode that most likely has NOTHING to do with the proof or application of the proof itself...). Third, the plots of the show are
  • There's always some way to simplify these problems. In the future they will have weeks of lecture on the solution and then at the end tell you that all you have to do is assume the inputs are periodic with no noise and then all you have to do is take the limit to infinity and it becomes a constant. Duh.
    • I have a feeling that if I understood this comment, it would make me laugh.
    • Re: (Score:3, Funny)

      by chromatic ( 9471 )

      You're thinking of physicists, who can prove this hypothesis for all prime numbers which are perfectly spherical and exist in a perfect vacuum.

  • Good Will Hunting when you need him? He'd have figured this out overnight.
  • by Anonymous Coward on Thursday March 20, 2008 @02:52PM (#22810800)
    If they'd have left it alone in 1858 we wouldn't be having this trouble. If it ain't broke, don't fix it!
  • question (Score:3, Interesting)

    by mapkinase ( 958129 ) on Thursday March 20, 2008 @02:57PM (#22810876) Homepage Journal
    Riemann zeta function is the "mother of all L-functions".

    zeta(s)=sum(n=1, inf)(1*n^-s)

    Dirichle L-function is defined as

    L(f, s)=sum(n=1, inf)(f(n)*n^-s)

    so when f(n)=1, Dirichle L-function becomes Riemann zeta function.

    L-function is just another representation (called Euler product) of Dirichle L-function.

    L(f, s)=prod(prime p=1, inf) P(p, s)

    where

    P(p,s)= 1 + f(p)p^-s + f(p^2)p^-2s + ...

    The Euler product I figured must work similar to the usual prime number decomposition: you got the sum of 1's and you got a product of primes.

    That is how far I got.

    Now what the heck are degrees of those L-functions?

    • by jlowery ( 47102 )

      Now what the heck are degrees of those L-functions?

      Fahrenheit?

    • Re:question (Score:4, Informative)

      by l2718 ( 514756 ) on Thursday March 20, 2008 @05:34PM (#22812826)

      Now what the heck are degrees of those L-functions?

      This is where things get technical. The Riemann Zeta-function $\zeta(s) = \sum_n n^{-s}$ has the Euler product representation $\zeta(s) = \prod_p \left( 1 - p^{-s}\right)^{-1}$. Similarly, the Dirichlet L-functions $L(s;\chi) = \sum_n \chi(n)/(n^s)$ have the Euler product $\prod_p L_p(s;\chi)$ with $L_p(s;\chi) = 1/( 1 - \chi(p)/(p^s))$. In both cases, the factor at each prime $p$ takes the form $1 / ( 1 - a(p)/p^s )$, for some number $a(p)$ depending on $p$. We think of this factor as a the inverse of a polynomial of degree 1 in the variable $p^(-s)$ (the polynomial is $P(T) = 1 - aT$).

      Similarly, to GL(3) Hecke-Maass forms such as the ones computed by Booker and Ce Bian, there is an attached L-function $L(s;f)$ which can be represented as an Euler product, $\prod_p L_p(s;f)$. This time, however, the local factors $L_p(s;f)$ are the inverses of cubic polynomials, that is $1/L_p(s;f)$ takes the form $P(p^-s)$ where $P(T) = 1 - aT - bT^2 - cT^3$ for some coefficients $a,b,c$ depending on $p$ (and on $f$, of course). This is why we call it an L-function (or Euler product) of degree 3.

      Using the Fundamental Theorem of Algebra, it is common to factor the polynomial $P(T)$, and write it in the form $\prod_{j=1}^{3} ( 1 - \alpha_j(p) T)$. Thus an Euler product of degree $d$ takes the form:

      \prod_p \prod_{j=1}^{d} 1/(1-\alpha_j(p) p^{-s})
    • Re: (Score:2, Informative)

      by MrSniffer ( 559920 )
      The "degree" is defined in this brief overview of the math, shown using conventional notation. http://www.aimath.org/news/gl3/technical.pdf [aimath.org] An overview of this result can be found at this page http://www.aimath.org/news/gl3/ [aimath.org]
  • Of course, as a scientist I do. But won't it also slaughter internet based commerce?
  • Who read his name as Sybian?
  • by Bromskloss ( 750445 ) <auxiliary.addres ... nOspAm.gmail.com> on Thursday March 20, 2008 @03:34PM (#22811462)

    ...before 1859, when cars were pulled by horses and the Riemann hypothesis was still not unproven. Those were they days, I tell you, those they were.

  • Submitter here. Right after hitting submit, I realized I'd forgotten to link to marginal revolutions, an economics blog that pointed me to the story.
    http://www.marginalrevolution.com/marginalrevolution/2008/03/assorted-link-4.html [marginalrevolution.com]
    http://www.marginalrevolution.com/ [marginalrevolution.com]
  • Sage and L-functions (Score:3, Interesting)

    by mhansen444 ( 1200253 ) on Thursday March 20, 2008 @07:04PM (#22813808)
    This article is related to Sage ( http://www.sagemath.org/ [sagemath.org] ), a free open-source math project. The article is about a computation (not using Sage) of an L-function, a computation about that L-function (using Sage), and a major new NSF-funded initiative to compute large tables of modular forms and L-functions that William Stein (director of the Sage project) is co-directing, which will have a large impact on Sage development.
  • So how long till we can use this to calculate the exact mass of a higgs boson particle?
  • I did not understand even one bit from the problem description, so I would like to approach this from another perspective: is there any practical benefits in proving the Riemann Hypothesis?

Every nonzero finite dimensional inner product space has an orthonormal basis. It makes sense, when you don't think about it.

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