Riemann Hypothesis Proved? 454
Theodore Logan writes "Has the Riemann Hypothesis finally been proved? The proof is a couple of months old, and to the best of my knowledge a Swedish newspaper is the only one to take up the story yet, so there is certainly a possibility that this is a hoax, or a less than watertight proof. But if it turns out to be the real thing, it will, apart from winning the authors eternal fame and glory for finding the holy Grail of modern math, provide them with a cool $1 million as they claim the first Millennium Prize." We had a story a while back about this as well.
Riemann hypothesis (Score:5, Funny)
um... (Score:4, Funny)
"A proof of the Riemann's hypothesis (RH) about the non-trivial zeros of the Riemann zeta-function is presented. It is based on the construction of an infinite family of operators D^{(k,l)} in one dimension, and their respective eigenfunctions \psi_s (t), parameterized by continuous real indexes k and l. Orthogonality of the eigenfunctions is connected to the zeros of the Riemann zeta-function. Due to the fundamental Gauss-Jacobi relation and the Riemann fundamental relation Z (s') = Z (1-s'), one can show that there is a direct concatenation among the following symmetries, t goes to 1/t, s goes to \beta - s (\beta a real), and s' goes to 1 - s', which establishes a one-to-one correspondence between the label s of one orthogonal state to a unique vacuum state, and a zero s' of the \zeta. It is shown that the RH is a direct consequence of these symmetries, by arguing in particular that an exclusion of a continuum of the zeros of the Riemann zeta function results in the discrete set of the zeros located at the points s_n = 1/2 + i \lambda_n in the complex plane."
What the fuck?
GREAT SCOTT!!! (Score:5, Funny)
On a related note.... (Score:1, Funny)
Point to a random cell, and shout "That should be a 3". Then turn and walk away just as quickly.
Really pisses them off.
Translation (Score:5, Funny)
Classic matteproblem able have got a solution
One of mathematics superb olösta problem, the so call Riemannhypotesen, able now have got a solution, 144 year after that that Bernhard Riemann publish sina mind if a special equation, as in its luck is förknippad with primtalen.
If the really am exposing themselves that certificates am holding able they two problemlösarna so småningom give a receipt out one million dollar in reward.
Year 1900 was gathering the world most outstanding mathematics to a conference in Paris. Wonder that present David Hilbert, the terms rankings mathematical think, 23 problem as sedan arrived that affect mathematics wonder heal 1900- digits, and than today. One of these problem each Riemannhypotesen, and defiance superb efforts has it stay olöst. IN November 2002 publish yet Carlos Castro from Clark Atlanta University, Atlanta, America, and Jorge Mahecha from University perceive Antioquia, Centre queue, Colombia a one proposal to solution.
The reward on one million dollar as exhibitor of American Clay Mathematics Institute sheep they yet nots out traitor one year behind publication. This for that second mathematics bark poll term that police accomplishment and watch if the really is accurate.
- About this is truly is the a grand sensation. This is a creature of problem as am claiming great effort entrance a eventual solution able verify. Tusentals mathematics the world over will pounce this and inspect certificates with a magnifier, says Andes Karlqvist, mathematics, professor in data and manager for Polarforskningssekretariatet.
He am declaring that certain of Hilberts problem rather is problemområden than separate problem. A bit had also word if under these term as gone. If now Riemannhypotesen is absolved so is tens of they 23 problems absolved, seven is olösta, five is part absolved and one is nots inferior current.
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Mathematics have the latest decade deployed very quickly, and the cheers article one aid as it olds 1900- digits mathematics nots be able anticipate datorn. Day all prompt and major datorer able manipulate huge amount speech and on short term make computations as formerly each impossible for a mans although he/ she was working a good deal currency with sina figure.
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Bengal Jonsson
New Businessplan?! (Score:-1, Funny)
Q.E.D!
The proof is... (Score:5, Funny)
Of course (Score:5, Funny)
It also proves that all non-trivial zeros are in the line Re(s) = 1/2. This is important because it humbles people without a very wierd Mathematical background, by informing them thre is such a this as trivial and non-trivial zeros. It may also get the Math guys some more girls.
Re:Translation (Score:1, Funny)
Re:Attempt at putting it in more layman's terms. (Score:3, Funny)
Honestly, you basically just translated that gobbledeegook from Latin to French for me. I still don't really understand what it all means, but I shall now do what I have done in the past for articles related to extremely complex mathematical hypothesis (hypothesese?)... I'll just nod my head, tell myself "Sure! But of course!" and move on to look for more "+5 Funny" comments.
Then maybe get back to work too.
oh Riemann you're so fine... (Score:5, Funny)
That is the WORST pickup line I have ever heard.
gosh, gee willakers (Score:4, Funny)
While the linked site does provide a layman's interpretation of the topic, when you first click to that page you are presented with:
Two Plus Two Equals Four
Thought we had all been trolled... :)
Re:Attempt at putting it in more layman's terms. (Score:2, Funny)
Ah, c'est une belle langue. vous devriez apprendre francais autrefois. ^_^
(I know, it's an anglicism, but it's good enough.)
But.... (Score:3, Funny)
Eu4ria
Re:Attempt at putting it in more layman's terms. (Score:5, Funny)
I was with you right up to the point where you started typing.
To do this, we are going to use the operators D^{(k,1)} and their respective vectors \psi_s (t), such that using D^{(k,1)} on \psi_s (t) will produce k*(\psi_s (t)), where k is some non-zero constant. Unfortunately though, we have to show a way to product all of these operators. So the "construction of" the operators will be contained within the proof.
ERROR: STACK OVERFLOW! SYSTEM POWERING DOWN...
So if this is proven to be true... (Score:3, Funny)
Re:Crypto applications (Score:5, Funny)
read the sales figures for pop albums.
I heard two laymen discussing this... (Score:5, Funny)
Construction Worker Joe: I think the non-trivial zeros of the zeta-function are of the form 1/2 +- i*theta_n
Construction Worker Larry: I agree. It's clear when you consider the operators D^{(k,1)} and their respective vectors \psi_s (t)
Construction Worker Joe: Of course, so long as using D^{(k,1)} on \psi_s (t) will produce k*(\psi_s (t))
Construction Worker Larry: Yeah. Joe, you'd better make sure the Eigenvectors of those two boards you're nailing together have a dot product of zero. The last time the boards weren't orthogonal, the boss had a fit!
Construction Worker Joe: Yeah, whatever. Hey, check out that girl's hyperbolic curves!
Re:Translation (Score:5, Funny)
I suppose if I were about to win a million dollars, my luck would be förknippad with primtalen, too.
Re:um... (Score:5, Funny)
(/me lobbies for the changing of "Off-Topic" moderation to "Orthogonal to Topic")
Re:Attempt at putting it in more layman's terms. (Score:3, Funny)
Wiggum: Whoa, whoa, slow down, egghead.
Frink: -- but suppose we extend the square beyond the two dimensions of our universe, along the hypothetical Z axis, there.
Everyone: (gasps)
Frink: This forms a three-dimensional object known as a "cube", or a "Frinkahedron" in honor of its discoverer.
Homer: Help me! Are you helping me, or are you going on and on?
Frink: Oh, right. And, of course, within, we find the doomed individual.
Watertight Proof? (Score:3, Funny)
I read this as waterproof tights for some reason... had visions of Batman in a wetsuit.
In that case -- Yay! I win a million dollars! (Score:3, Funny)
The Riemann hypothesis asserts that all interesting solutions of the equation z(s) = 0 lie on a straight line.
Well, graphing s versus z(s), if z(s) is always zero, then obviously all values of s solving that equation lie on the s axis, which is a straight line. QED.
Sheesh. That wasn't so hard.
Re:HINT: Go read the comments on the previous arti (Score:1, Funny)
Explained With Pictures (Score:5, Funny)
Re:I heard two laymen discussing this... (Score:4, Funny)
Re:I heard two laymen discussing this... (Score:3, Funny)
Construction Boss wanders off...
Construction worker Larry: Stupid pointy haired fuck, doesn't know that the dot product of two perpendicular vectors is 0.
Construction worker Joe: Yeah, hell, the fucking cross product isn't even a scalar!
Construction worker Larry: (in a serious tone) Now be fair, he could have meant (snicker) the zero vector. (snicker)
Construction worker Joe: (laughing) I suppose if I was sliding the nail along the stud.
the scene devolves into derisive snickering.
Re:Attempt at putting it in more layman's terms. (Score:3, Funny)
Homer: Say it in English, Doc.
Doctor Hibbert:You're going to need open-heart surgery.
Homer: Spare me your medical mumbo-jumbo.
Doctor Hibbert: We're going to cut you open and tinker with your ticker.
Homer: Could you dumb it down a shade?
Re:I heard two laymen discussing this... (Score:3, Funny)
Re:NSA found it already? (Score:3, Funny)