Space Elevators Could Be Lethal 428
Maggie McKee writes, "A new study reports that passengers on space elevators of current design could be killed by radiation. Even traveling at 200 kilometers per hour, passengers would spend several days in the Van Allen radiation belts, long enough to kill them." Looks like the elevator scientists will get this one solved before liftoff.
The two rubs (Score:5, Informative)
The article says that you may not want to add shielding because of the added mass. Wikipedia [wikipedia.org] says that "an object satellite shielded by 3 mm of aluminum will receive about 2500 rem (25 Sv) per year." I don't know how this would translate for people going through the area, but 3 mm of aluminum doesn't weigh much.
Re:Aqua viva (Score:5, Informative)
Re:Oh, the horror! (Score:2, Informative)
Re:Oh, the horror! (Score:5, Informative)
Re:The two rubs (Score:4, Informative)
Re:I've always wondered ... (Score:2, Informative)
Hybrid solution (Score:4, Informative)
We've made it through the Van Allens before, we'll figure out how to do it again.
And, anything can kill you, really, so long as it's an action. Space elevators aren't lethal in and of themselves. Organ failure due to blunt trauma, rapid depressurization, radiation poisoning; these can kill you. An elevator cannot. It's an inanimate object. Well, unless you're on acid. Then you're on your own, kid.
Re:space elevator - environmental impact (Score:3, Informative)
No significant difference (Score:3, Informative)
Acceleration toward an object due to gravity is given by g = GM/r^2, where G = 6.67e-11 is the gravitational constant, M is the mass of the object, and r is the distance from the center of mass of the object. The mass of the earth is about 5.97e24 kilograms, and its mean radius is about 6.37e6 meters. Thus, the acceleration due to gravity at the planet's surface is approximately (6.67e-11 * 5.97e24) / (6.37e6^2) = 9.81 m/s^2.
Go up another measly 500 kilometers, and your new acceleration is approximately (6.67e-11 * 5.97e24) / (6.87e6^2) = 8.44 m/s^2. That's only a 14% difference; a very noticeable reduction, but not enough to have significant savings. Your rocket fuel wouldn't go much farther at all, at least when the goal of the space elevator is to reduce cargo costs by orders of magnitude.
Re:I smell problems (Score:3, Informative)
Re:The two rubs (Score:3, Informative)
Re:Jeez (Score:3, Informative)
Realistically, some kind of reusable passenger rocket or space plane is still desirable in order to get passengers and sensitive kinds of freight through the Van Allen Belts to a Space Station (probably the one at the top of the elevator) in a rapid manner, so as to side step the issue entirely.
None of this is to say that a Space Elevator is a bad idea, FAR from it, but it may not necessarily to sensible to expect the same infrastructure to be able to accomodate both passengers and freight. I would argue that this is actually one of the major problems with the Space Shuttle's design. Being committed to a Freight and Passenger vehicle resulted in having to do a Saturn V scale launch just to get anybody into orbit, in addition to the limits this placed on any number of satellites launched with the shuttle. Had we designed a smaller, simpler vehicle, specifically for passengers (as the did the Russians) launches would have been MUCH cheaper, on a Saturn I or a modern Atlas scale. Additionally we would have been able to achieve significantly higher orbits (What if we didn't have to worry about Hubble's orbit decaying? Among any number of other advantages) Reliance on a Space Elevator for all our Space travel also gives a rather significant single point of failure.
Re:Math error? (Score:4, Informative)
Re:C'mon, COMMON SENSE! (Score:5, Informative)
I don't think you've thought it through. Of course angular momentum isn't free, but that doesn't mean that you have to send things down the cable to keep the elevator from deorbiting. Once a unit of payload mass is lifted past the center of gravity of the cable, it effectively becomes part of the counterweight, increasing the amount of mass the space elevator is capable of lifting from then on (up to the point where the increased tension would cause the cable to snap, anyway).
So where does the "non-free" angular momentum come from? From the angular momentum of the Earth, of course... every time something goes up the elevator, the Earth spins a tiny bit slower -- similar to how an ice skater spins more slowly after she extends her arms. Fortunately, the Earth is massive enough compared to us humans that we'd never conceivably make a noticeable dent in Earth's momentum reserves (famous last words?
That said, a second parallel "down" elevator near the "up" elevator might be useful at some point, for more efficient round trips. But that's for later, the first task is to get a one-way elevator working.
Re:Math error? (Score:5, Informative)
Saying the cable is in geosynchronous orbit is analogous to saying that the cables on a suspension bridge are "flying".