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Space Science

The Deepest Photo Ever Taken 218

Astroturtle writes "Astronomers using the Hubble Space Telescope's powerful new Advanced Camera for Surveys (ACS) have taken the deepest visible-light image ever made of the sky. The 3.5-day (84-hour) exposure captures stars as faint as 31st magnitude, according to Tom M. Brown (Space Telescope Science Institute), who headed the eight-person team that took the picture."
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The Deepest Photo Ever Taken

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  • article (Score:3, Informative)

    by CowBovNeal ( 672450 ) on Saturday May 10, 2003 @11:42PM (#5929007) Homepage Journal
    May 7, 2003 | Astronomers using the Hubble Space Telescope's powerful new Advanced Camera for Surveys (ACS) have taken the deepest visible-light image ever made of the sky.

    The 3.5-day (84-hour) exposure captures stars as faint as 31st magnitude, according to Tom M. Brown (Space Telescope Science Institute), who headed the eight-person team that took the picture. This is a little more than 1 magnitude (2.5 times) fainter than the epochal Hubble Deep Fields, which were made with the Hubble's Wide Field and Planetary Camera 2. It is 6 billion times fainter than what can be seen with the naked eye.

    Brown and his colleagues chose to point at a spot 1 southeast of M31, the Great Andromeda Galaxy, in order to get a census of faint stars populating M31's outer halo. The full ACS image is about 3.1 arcminutes square, the size of a sand grain held at arm's length against the sky. The ACS magnifies this small field into a vast panorama of some 300,000 stars and thousands of faint background galaxies. At M31's distance of 2.5 million light-years, the faintest of the stars are slightly less luminous than our Sun. A large fraction of the most distant galaxies appear patchy and irregular, testimony to the collisions and mergers in the early universe that built up the familiar galaxies we see closer around us today.

    Most of the stars in the image indeed proved to be in M31's halo, judging from their colors and brightnesses. Moreover, they show a surprisingly wide range of estimated ages -- from 6 to 13 billion years, compared to 11 to 13 billion years for our Milky Way's halo stars. Perhaps M31 has captured and torn apart younger dwarf galaxies than our Milky Way has done. Or perhaps M31 underwent a massive, disruptive merger with a single large galaxy billions of years ago; in this scenario some of M31's younger disk stars could have been flung into its halo. Or maybe some combination of these events triggered waves of star formation in regions that ended up in M31's outer fringes.

    The image was made in two colors: near-infrared and "visual" (a band spanning the part of the spectrum running from yellow through green). The renditions displayed here were crafted to resemble true-color views by interpolating from these two colors. These vignettes each show only about 1 percent of the ACS image. The full image is available from the Hubble Telescope's press site at various qualities and sizes (up to 128 megabytes), along with more highlights and a finder chart showing its relation to M31.

    Plans are afoot for an even deeper "Ultra-Deep Field," which will use ACS for longer exposures in four colors and go slightly fainter still.
  • by ChadN ( 21033 ) on Sunday May 11, 2003 @12:05AM (#5929096)
    While I'm no expert, I believe the answer is simply "gyroscopes". Very good ones, I'm sure. Also, they use reference stars to correct the gyroscopes when they drift.
  • by bertok ( 226922 ) on Sunday May 11, 2003 @12:05AM (#5929097)
    Direct link to the full-resolution JPEG. (~4.9MB)

    http://imgsrc.hubblesite.org/hu/db/2003/15/images/ a/formats/full_jpg.jpg [hubblesite.org]
  • by SILIZIUMM ( 241333 ) on Sunday May 11, 2003 @12:06AM (#5929101) Homepage
    See also the press release [hubblesite.org] with tons of photos. Enjoy your new wallpaper ! :)
  • by deathcow ( 455995 ) on Sunday May 11, 2003 @12:06AM (#5929102)
    Many spacecraft have small jets that push them into different positions in space. Hubble has no jets because the exhaust gas from jets could damage its delicate mirrors. Instead, Hubble uses momentum to move.

    When Hubble needs to move to a new target, engineers on Earth radio a signal to the HST flight computer. The flight computer then activates the Reaction Wheels.

    Reaction wheels are heavy fly wheels that spin. As they spin, the momentum from their motion causes the telescope to move. There are four Reaction Wheels. By spinning each one at a certain speed and in a certain direction, engineers can point the telescop e anywhere they want.
  • hubblesite.org (Score:5, Informative)

    by zaneIO ( 606505 ) on Sunday May 11, 2003 @12:07AM (#5929104)
    Here is a link to a higher resolution image.
    Hubblesite.org [hubblesite.org]
  • Re:3.5 Day Exposure? (Score:5, Informative)

    by deathcow ( 455995 ) on Sunday May 11, 2003 @12:09AM (#5929115)
    Astrophotos are commonly made by combining many shorter exposures. Each additional exposure improves the signal to noise ratio yielding progressively greater detail.

    As far as color and reciprocity, Hubble color shots are not always as the eye sees them. The famous "pillars of creation" shot for example, presented the light from oxygen ionization in one color, the light from sulfur ionization in another color, the light from hydogren ionization in another color.
  • by I'm a racist. ( 631537 ) on Sunday May 11, 2003 @12:10AM (#5929120) Homepage Journal
    I haven't read the article, but I do have a degree in astrophysics, so I can guide you in how to calculate it.

    There are a few different ways of measuring magnitude (apparent, bolometric, etc). Bolometric is essentially the integral over all wavelengths. I'm guessing they didn't do a real bolometric measurement, but I could be wrong.

    Anyway, the relationship between intensity (I) and apparent magnitude (m) is
    m = -[19 + (2.5).log(I)]
    Intensity is in units of power/area, such as W/m^2 or ergs/cm^2 (cgs units are oddly popular in astronomy).

    If they did do a bolometric measurement, you can pretty easily manipulate this relationship to reflect that.

    Now, from the power, knowing the wavelength(s), and using the fact that the energy per photon is the frequency times Planck's constant... and thus you can find the number of photons per unit time per unit area. Which, when coupled with the known exposure time, will give you the total number of photons.
  • by jeffrey1681 ( 148195 ) on Sunday May 11, 2003 @12:15AM (#5929136)
    The image is not actually a single exposure of 3.5 days in duration, but is actually made from 250 separate exposures taken from Dec. 2 to Jan. 11, 2003. The total exposure time was 3.5 days.

    For those who are interested, the original hubble press release is located here [hubblesite.org].

    The site includes the image in a variety of different formats, including a 123 MB tiff file.
  • Re:3.5 Day Exposure? (Score:5, Informative)

    by Liquid Tip ( 672473 ) on Sunday May 11, 2003 @12:23AM (#5929158) Homepage
    CCDs do not suffer from Reciprocity failure like film does. However there are other problems that will turn long exposures into junk (such as cosmic rays as HST is not sheltered by the earths atmosphere!). So many shorter exposures are taken and then coadded to make a 3.5 day exposure.
  • by neurostar ( 578917 ) <{moc.novirp} {ta} {ratsoruen}> on Sunday May 11, 2003 @12:23AM (#5929163)

    As they spin, the momentum from their motion causes the telescope to move.

    Well, it's techincally a litter different than that. The wheels don't actually cause hubble to translate within a plane. Instead they rotate hubble. By turning the spinning wheels, a torque is exerted on hubble, causing it to rotate.

    neurostar
  • by Anonymous Coward on Sunday May 11, 2003 @12:43AM (#5929224)
    Modern optical/IR/UV telescopes typically have a large primary mirror, which reflects light back to a smaller secondary, which reflects the light through a small hole in the primary to the detectors. The secondary is supported by little rods. It is diffraction of light by those supports which cause stars to have distorted shapes.

    (Astronomers understand the diffraction issues very well... it's usually not a problem; it just looks weird.)

    - A friendly neighborhood astrophysicist
  • by LMCBoy ( 185365 ) on Sunday May 11, 2003 @01:03AM (#5929271) Homepage Journal
    3.4 days is the effective exposure time, from stacking many shorter exposures. If HST integrated for 3.4 days without reading out the CCD, the entire chip would be saturated with cosmic rays, not to mention the fact that the Earth is typically in the way for half the orbit(*), limiting individual exposure times to about an hour or so.

    (*) except for a small patch of sky called the CVZ: continuously visible zone

    BTW, if you're keeping score at home, 30th magnitude is 1 trillion times fainter than the human eye can see!

    [*shameless plug* Tom Brown is using my thesis code to analyze these data :) ]
  • by Liquid Tip ( 672473 ) on Sunday May 11, 2003 @01:04AM (#5929277) Homepage
    The best way is to download the processed HST images and see what the count rate is for a faint star. Then multiply by the gain (in the header of the image) which will give you the number of photons detected. A way to guestimate the number of photons is to compare the flux of the faintest star with the Sun. At the Earth's distance the Sun has a flux of 1.36x10^6 erg s-1 cm-2 and the apparent mag of the sun is V=-26.8. If we assume that we have a star with V=31 mag (the 50% completeness level is V=30.7 mag) then the flux recieved from the star is given by: F2/F1 = 100^((m1-m2)/5) where F1 and m1 are the flux and magnitude of the sun and F2 and m1 refer to the star. This gives 1.03x10^-17 erg s-1 cm-2. Convert the ergs into photons by the de Broglie frequency (E=hv) where we assume that a V-band photon has a wavelength of 550nm or a frequency of 5*10^14 s-1. Thus, each photon carries 3.61x10^-12 ergs which gives a rate of 2.85x10^-6 photons s-1 cm-2. So a 3.5 day exposure is 302400 secs and HST has an aperature of 240 cm so we get about 50000 photons at the entrance of the telescope. Remember.. detection of these sources means having a low background so that these photons are not lost in noise! I should also point out that HST does not leave the shutter open continuously for 3.5Hs, instead it takes a series of short exposures that are co-added. I hope this helps (and doesn't freak people out!)
  • Will be about 20 billion light years, since we think the universe is about 20 billion years old.

    For an interesting article, see:

    http://www.sciam.com/article.cfm?colID=1&article ID =000F1EDD-B48A-1E90-8EA5809EC5880000

    On parallel universes. Very interesting reading. If you're at a university, you will be able to browse the site's archives and access the nice PDF version of the article (which has the pictures supersized to full-page size).
  • by jeffrey1681 ( 148195 ) on Sunday May 11, 2003 @01:10AM (#5929297)
    Almost all modern optical/IR/X-ray telescopes use a CCD to capture the light that is incident on the telescope. Each pixel in the CCD can hold a certain number of electrons (which are produced when a photon hits the pixel). When that number is exceeded, usually through too many photons hitting the same pixel as in this case, the electrons spill over into the surrounding pixels. This is called blooming and produces the spikes that you see in the image. So basically, the spikes mean that the star is overexposed.
  • Re:Streaks (Score:5, Informative)

    by Liquid Tip ( 672473 ) on Sunday May 11, 2003 @01:15AM (#5929311) Homepage
    The "streaks" centering on stars are diffration spikes from the secondary mirror support. The colour alternates as different wavelenghts cause different diffration spacings.

    The big bright cluster is actually a member of Andromedae (M31). Very impressive! The appearance of fuzziness is because the CCD oversamples the resolution of the telescope - which is necessary for good photometry - if you want it "sharp" then just bin the pixels by 2x2 or 3x3 or whatever looks best!
  • Mirror of full JPG (Score:5, Informative)

    by idiot900 ( 166952 ) on Sunday May 11, 2003 @01:24AM (#5929335)
    [wustl.edu]
    http://wuarchive.wustl.edu/users/tom/mirrors/hub bl e/full_jpg.jpg

    is a mirror of the full JPEG - about 5M. Enjoy.
  • Comment removed (Score:5, Informative)

    by account_deleted ( 4530225 ) on Sunday May 11, 2003 @01:28AM (#5929350)
    Comment removed based on user account deletion
  • by Nintendork ( 411169 ) on Sunday May 11, 2003 @01:35AM (#5929372) Homepage
    This is the official site [hubblesite.org] where the photos are.

    -Lucas

  • Re:All in all... (Score:3, Informative)

    by plip ( 630579 ) on Sunday May 11, 2003 @01:39AM (#5929384)

    Not Several Millions, we're talking Billions...

    According to http://hubble.nasa.gov/faq.html [nasa.gov] it cost $1.5 billion Plus another $230-250 million each year for maintenence. Estimated costs to fix the lens problem on the telescope were $20 million. Since the Hubble was launched in 1990 and is planned to operate until 2010, that's $230M per year for 20 years = $4.6 Billion + the $1.5 Billion initial cost. That's a total cost of operation equal to $6.1 Billion (low estimate that doesn't include the cost of engineering and scientific knowledge needed for this to happen).

    In my opinion, the information it sends back is priceless to humanity, and well worth whatever cost it takes.
  • by LMCBoy ( 185365 ) on Sunday May 11, 2003 @01:47AM (#5929407) Homepage Journal
    You're right, if you take deepest image to mean "image of most distant objects" instead of "faintest objects". However, the Universe is 13.7 Gyr old, not 20 Gyr.

    Here's your deepest image then:
    http://map.gsfc.nasa.gov/m_ig/020598/020598 _ilc_64 0.jpg

    That's from the recent WMAP mission, which mapped the cosmic microwave background in exquisite detail, pinpointing the age of the Universe (and many other cosmological parameters) to high precision. You're looking at an all-sky image of the Universe as it looked when it was 100,000 years old, and became transparent for the first time. IOW, you are literally seeing the fires of creation.

  • MOD PARENT DOWN. (Score:2, Informative)

    by Anonymous Coward on Sunday May 11, 2003 @02:04AM (#5929450)
    Moderators: Please don't encourage this guy in any way, even if this comment of his may very well contribute to the technical discussion.

    He doesn't deserve positive karma until he learns some respect. When he learns to treat people of all colors as he wishes to be treated himself, then perhaps he can contribute to the discussion in a worthwhile manner.

    What goes around, comes around. Paranoid delusions about people of other races (sexes / political and religious beliefs) are so 1700's and have no place in an advanced civilisation.
  • by TMB ( 70166 ) on Sunday May 11, 2003 @07:36AM (#5930187)
    I've read that paper, and there's a major problem - they do the calculation in the direction of propogation, but then try to use the result in the transverse direction. You can't do that. No one's done the calculation in the transverse direction, so we still don't know what the theoretical prediction should be.

    [TMB]
  • by Anonymous Coward on Sunday May 11, 2003 @09:04AM (#5930369)
    Oh yeah? Let me quote from the journal of that "I'm a Racist" dude:

    "Traits come in groups. More than one trait is needed to clearly identify a taxonomic class. Niggers have dirty skin, pubic hair on their heads, broad and flat noses, etc. Why can't being a lowlife, useless, stupid, lazy, criminal shitmonkey be considered part of such a group of common traits? Just because some things are negative we shouldn't consider them??

    As for the nature vs. nurture issue, we'll put that aside for this discussion (it's well outside the scope anyway). Suffice it to say that, if a nigger raises a nigglet, the point becomes moot.

    "Anti-racists" deny the facts of reality because they wish the world followed their ideal. I live in reality. In reality niggers/spics/kikes/chinks/dotheads/etcetera lower the quality of life for everyone. For that they should fucking die.


    How can someone be so fucking stupid and not realize that THEY are the ones lowering the quality of life for everyone? Whenever I've been ripped off in my life, it was a white man. I'm not that old okay, 38, but still I think stupid fucks like that guy and their sympathizers should get fucking locked up or at least sterilized. They make me ashamed of being white.

    It's just a game, yeah right. You do realize that kids love FPS games, huh? I'm against censorship, but at least we shouldn't treat it like any random game?! FUCKING BRAINLESS FOOL.
  • The Hubble has an instrument called the Fine Guidance Sensor (FGS) package. Given two stars that are bright enough near the sky location of your desired target, Hubble will be able to guide to within sub-pixel accuracy for as long as you like.

    If only one star is available, guiding is still possible, but the field may slowly rotate, since one star only provides one of the two needed pointing constraints (of position and orientation).

    A big project in preparation for Hubble was the creation of the Hubble Guide Star catalog, exactly for this purpose -- to make sure that given what people would want to observe, there would always be enough guide stars within an acceptable distance!

    for more information, see here [stsci.edu] if you're interested! If you're ambitious, you can even read the instrument handbooks for yourself: here [stsci.edu]
  • Comment removed (Score:3, Informative)

    by account_deleted ( 4530225 ) on Sunday May 11, 2003 @02:26PM (#5931678)
    Comment removed based on user account deletion
  • by jstott ( 212041 ) on Monday May 12, 2003 @11:49AM (#5936862)
    Why four points? Why do we see them even when the star itself is not in the picture (look on the top border for examples, like the one almost directly in the middle)?

    No quantum mechanics, just plain ol' classical optics. Those are diffraction patterns. Crosses are the Fourier transform of a square, so I assume their aperature stop is a square.

    -JS

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