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Space Science

Earth's Little Brother Found 432

loconet writes "The BBC is reporting that astronomers have discovered the first object ever that is in a companion orbit to the Earth. Asteroid 2002 AA29 is only about 100 metres wide and never comes closer than 3.6 million miles to our planet."
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Earth's Little Brother Found

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  • by StupendousMan ( 69768 ) on Monday October 21, 2002 @09:35PM (#4500928) Homepage

    JPL has a very nice tool for looking at the orbits of asteroids. Go to

    http://neo.jpl.nasa.gov/orbits/ [nasa.gov]

    for the general case. For 2002AA29 in particular, you can use

    http://neo.jpl.nasa.gov/cgi-bin/db?name=2002AA29&g roup=all&search=Search [nasa.gov]

    Keep in mind that the orbital solution is based on only a short arc: only 28 days, about one twelfth of a complete revolution. Our estimates of the orbital parameters -- and behavior -- could change quite a bit over the next few months.

  • by ocie ( 6659 ) on Monday October 21, 2002 @09:36PM (#4500941) Homepage
    Interesting physics, but Kepler's third law says:

    The squares of the periods of the planets are proportional to the cubes of their semimajor axes
    (http://home.cvc.org/science/kepler.htm).

    So the mass of a planet has nothing to do with its orbital period (well, assuming it is small enough that it doesn't make the sun orbit it). So anything placed at Earth's distance from the sun and moving at the same speed would orbit the sun in the same path the Earth does regaurdless of its mass.
  • by targo ( 409974 ) <targo_tNO@SPAMhotmail.com> on Monday October 21, 2002 @09:39PM (#4500957) Homepage
    roughly the same orbit around the sun, a much smaller mass has to travel MUCH slower than the Earth to maintain that orbit.

    Wtf? Orbital velocity is a constant that depends only on the mass of the parent body, as long as the orbiting body is significantly lighter.
    After all, geosynchronous satellites are all at approximately same height, although they have the same speed (to maintain synch), but different mass.

    The formula for calculating orbits is:
    T=2*pi*(a+h)/v
    where T = period, a = radius of the parent body, h = orbit height, and v = satellite velocity, which can be calculated from:
    v = sqrt(g/(a+h)),
    where g is gravitational acceleration of the parent body.
    You don't see the mass of the satellite anywhere here.
  • by GreenPhreak ( 60944 ) on Monday October 21, 2002 @09:48PM (#4501007)
    The reason this discovery is useful and more than 'whoop-de-doo' is because of what was mentioned in the end of the article: it is an extra-terrestrial body that is very close to the Earth. It would not be outside our reach to visit this object with current technology and learn more about the composition of asteroids and other minor planets in the solar system.

    It is also intriguing since no 'trojans' have been discovered for the Earth and this could signal that we do in fact have some. Trojans are asteroids that occupy the 4th and 5th Lagrangian points about a larger body (Jupiter has the most, due to its large mass). Because of the physics involved in a 2 body system where any additional bodies have negligible mass compared to the original 2, there are a few 'stable' points where the gravitational forces cancel out...these are known as Lagrangian points. L4 and L5 are co-orbital to the less-massive object (Jupiter, Earth, whatever).

    Although this object is not a trojan, since it has a horseshoe orbit and temporarily gets caught up in Earth's orbit, it suggests that there are bodies out there that could be trojans. Perhaps as our detection abilities progress, we will discover some Earth-trojans.

  • by DirtyJ ( 576100 ) on Monday October 21, 2002 @09:49PM (#4501020)
    From the description in the article and my knowledge of celestial mechanics, it sounds like this object is effectively bouncing back and forth between Earth's Lagrange points L4 and L5. These are points where the combination of gravitational pull from the Sun and the Earth would have the effect of allowing the object to maintain a stable orbit around the sun in what would otherwise be an unstable position.

    Basically, at a given orbital energy, or velocity, and object can orbit at a certain distance from the central mass (the Sun in this case). If it speeds up, it has to move to a smaller orbital radius. If it slows down, it moves to a larger orbital radius. In this case, it sounds like the following may be happening:

    (1) The asteroid is moving faster than the Earth, and so travels in a slightly lower orbit. When it gets to one Lagrange point, it will slightly overrun it, and the Earth's pull will send it to a higher orbit, stealing some of its kinetic energy. It then slows down and the Earth speeds away from it.

    (2) The now slower-moving, higher-orbiting asteroid moves backward with respect to the Earth, until the Earth catches up to it until it overruns the other Lagrange point. When that happens, the Earth pulls it into a lower, more energetic orbit, and it proceeds to speed away from the Earth.

    (3) go back to #1 and repeat.

    During the brief time that the Earth's influence on the asteroid is greater than that of the Sun, the asteroid technically becomes a satellite of the Earth.

    I could be wrong about all this, but at first read, this was how I interpreted things...

  • by Doomrat ( 615771 ) on Monday October 21, 2002 @09:54PM (#4501049) Homepage
    Has anybody noticed how the BBC news is the best mainstream source for geeky stuff?
  • Re:Horseshoe orbit? (Score:5, Informative)

    by Link310 ( 453668 ) on Monday October 21, 2002 @09:56PM (#4501063)
    http://www.paias.com/paias/home/Science/Newton/New t8Fig5Orbits.htm [paias.com] explains it. From what I understood, it's actually orbiting the L4 and L5 Lagrange points of earth.

    This picture [paias.com] illustrates it pretty well.
  • by geoswan ( 316494 ) on Monday October 21, 2002 @10:18PM (#4501181) Journal
    Of course, the part I don't get, *why* can't it hit the Earth? In roughly the same orbit around the sun, a much smaller mass has to travel MUCH slower than the Earth to maintain that orbit...

    I don't have the equation for the gravitational attraction between two bodies. But I know it is a function of the SUM of the masses of the two objects. So, how much do you think the sum of the masses of the sun and the Earth differs from the sum of the masses of the sun and 2002 AA29?

    There are lots of explanations of horseshoe orbits on the web. Basically, if two objects share the same, or very similar, orbits, they are attracted to one another. That gravitational attraction drains kinetic energy from the leading object, and slightly adds kinetic energy to the trailing object.

    The leading object, having lost energy, moves closer to the primary. Its year gets slightly shorter, and its actual velocity relative to the primary speeds up. Similarly, the trailing object moves farther away, and its year grows slightly longer.

    So the leading objects closer orbit has it revolve around the Primary more quickly, and it will slowly move away from the trailing object. Eventually the leading object is exactly opposite from the trailing object. According to the BBC article, this takes 95 years.

    Once the object that was leading is more than 180 degrees ahead in it orbit from the object that was trailing, their mutual attraction starts to add energy to its orbit, and raise it to a higher orbit. Similarly, the mutual attraction drains energy from the other object.

    What we have just seen is the two objects trade places. The object that was the trailing object is now the trailing object.

    It seems paradoxical that mutual attraction should tear the two object apart. Until you remember that the Sun's influence on the object's trajectories is much more important than their attraction to one another.

    At least that is my understanding of the BBC's article.

    How does this mechanism allow 2002 AA29 to be briefly captured by the Earth? I'd welcome an explanation of this.

  • by Anonymous Coward on Monday October 21, 2002 @10:22PM (#4501196)
    Yeah, BBC is pretty good, and I'd also suggest NPR. And the NYTimes are okay too, and Washington Post.
  • Re:Second Moon (Score:2, Informative)

    by gurensan ( 259321 ) on Monday October 21, 2002 @10:25PM (#4501211) Journal
    No. It's too small. It's like passing a hand-size natural magnet 50 feet away from iron filings.
  • Re:Horseshoe orbit? (Score:2, Informative)

    by Joe Kepler ( 615576 ) on Monday October 21, 2002 @10:32PM (#4501243)
    This [cornell.edu] is a nice simple explanation of horseshoe orbits.
  • by Doomrat ( 615771 ) on Monday October 21, 2002 @10:35PM (#4501258) Homepage
    Which is exactly why we'd want to be forgetting Fox news.
  • uh... 'scuse me? (Score:5, Informative)

    by TWX_the_Linux_Zealot ( 227666 ) on Monday October 21, 2002 @11:04PM (#4501372) Journal
    Here [queensu.ca] is Paul Wiegert's [queensu.ca] information on Cruithne, which has much of the same characteristic as this current space body, but his explanation actually makes sense for what appears to be a horseshoe orbit, when in reality it's only a horseshoe orbit from Earth's perspective, and is relatively sane looking when viewed off of the solar system plane.
  • Size Matters (Score:3, Informative)

    by JoeRobe ( 207552 ) on Monday October 21, 2002 @11:53PM (#4501599) Homepage
    I noticed a few people wondering how this would affect our planetary tides, orbit, etc. This would NOT affect the earth at all. Hell, it wouldn't even make that big of a crater if it hit us (why do I think I'm going to get flamed for that?)

    The thing is 100 meters wide. Imagine a 100 meter (300 foot) wide ball. If we just grabbed it and brought it to earth's surface (gently), it still wouldn't affect our tides at all. It's small enough to fit in a stadium. It's the size of a big hill. The point is that it wouldn't affect us at all.

    Also, the reason it wasn't seen that long ago was that it was too far away and too small to see with the naked eye. (we could barely see it with a scope).

  • by Guppy06 ( 410832 ) on Tuesday October 22, 2002 @12:21AM (#4501717)
    "In roughly the same orbit around the sun, a much smaller mass has to travel MUCH slower than the Earth to maintain that orbit."

    Follow along in your copy of Principia Mathematica and repeat after me:

    An object maintains linear velocity unless acted upon by an outside force.

    Force of sun on asteroid: outside force
    Force of asteroid on sun: not involved

    It doesn't matter whether the mass in question is you, a '57 buick or the Death Star. An object 1 AU away (on the average) from something with the mass of the sun orbits once every 365.2429 days, give or take.

    Galileo figured out in the 17th cenutry that all objects reguardless of mass fall at the same acceleration. Where have you been in the past 350 years or so?
  • Re:Confused... (Score:3, Informative)

    by BiOFH ( 267622 ) on Tuesday October 22, 2002 @01:05AM (#4501864)
    A companion is not the same as a satellite.
    That's all. A companion describes a similar orbit as another body. The Earth's moons have, necessarily, a slightly different orbit from the Earth if you plot them.

  • by Anonymous Coward on Tuesday October 22, 2002 @01:43AM (#4501992)
    Very good. Now solve the 3-body problem.

  • by Tim C ( 15259 ) on Tuesday October 22, 2002 @03:06AM (#4502240)
    Imagine if we measured in Kelvin, though... that would be confusing!

    Please; just subtract 273:

    >298K: t-shirt, shorts
    293K-298K:t-shirt, jeans
    etc...
  • by The Cydonian ( 603441 ) on Tuesday October 22, 2002 @03:09AM (#4502257) Homepage Journal

    A Trojan asteroid is "any planetoidal body at the triangular Lagrangian point of any two bodies" named thus because the Trojan asteroids of the Sun - Jupiter system are named according to the Illiad.(Wikipedia [wikipedia.org]). There's an interesting webpage on the Trojan asteroids in the Sun - Earth system here [queensu.ca]

  • Comment removed (Score:3, Informative)

    by account_deleted ( 4530225 ) on Tuesday October 22, 2002 @12:28PM (#4505078)
    Comment removed based on user account deletion

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