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Solar System in a Can May Reveal Hidden Dimensions
Posted by
Zonk
on Fri Jul 07, 2006 07:45 PM
from the you-can-get-them-in-cans dept.
from the you-can-get-them-in-cans dept.
dylanduck writes "A model solar system, made of tungsten and placed in space, could reveal hidden spatial dimensions and test alternative theories of gravity. If the system's 'planets' moved slightly differently to the way predicted by standard gravity, it would signal the presence of new physical phenomena." From the article: "Once at the Lagrange point, the artificial solar system would be set in motion inside the spacecraft. An 8-centimetre-wide sphere of tungsten would act as an artificial sun, while a smaller test sphere would be launched 10 cm away into an oval-shaped orbit. The miniscule planet would orbit its tungsten sun 3,000 times per year."
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Gotchas, we got em (Score:3, Interesting)
Re:Gotchas, we got em (Score:4, Informative)
And the spacecraft components themselves would exert gravitational forces on the spheres. These forces could be minimised by making the spacecraft as symmetrical as possible and putting its heaviest components as far from the artificial solar system as possible.
"Such an experiment would be quite challenging to set up, but I don't think it is technologically impossible," says MOND expert Stacy McGaugh of the University of Maryland, US.
Not impossible can be quite a stretch to feasible, though.
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Re:Gotchas, we got em (Score:5, Funny)
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Re:Gotchas, we got em (Score:5, Insightful)
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Re:Gotchas, we got em (Score:3, Informative)
Of course, the math for that is based on regular-old physics. It might not apply in higher-dimensional physics that these scientist hope to prove.
Of course, the article ignores the difficulty i
Re:Gotchas, we got em (Score:4, Informative)
The proof, involving triple integrals, is left for the reader.
Of course, designing a spacecraft that is as spherically symmetrical and uniform in density as possible will be difficult. TFA refers to this, and before much money is spent on this project, one would hope some number-crunching is done to see how extreme the effect is.
Another problem will be microgravity. Orbital velocity is dependent upon the distance from the center of the object being orbited. In Earth orbit, even a few inches difference can produce a velocity gradient that can result in minute accelerations. At L2, some of these effects might be minimized, although again, number crunching should be done.
The late Robert L. Forward proposed a system of massive spheres that could flatten spacetime in a local region [aps.org]. To further minimize extraneous effects due to microgravity, a system like this might need to be used. One advantage would be that this same system might eliminate some of the problems due to assymetry in the spacecraft. One of the problems with this situation would be mass lofted, which currently tends to be expensive, and additional calculations that might be required to analyze the data.
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Re:Gotchas, we got em (Score:4, Informative)
Calculating the position of the moon throughout the month and deriving the orbit wasn't something I did until I got out of college. It's well within the capability of a Freshman physics student, so in theory we could have confirmed the inverse square law to a decent level of precision.
Tightening the exact value of that exponent (is it really -2?) further is the purpose of the proposed experiment.
If you know that gravity follows an inverse square law, then you know that inside a uniform sphere the gravitational acceleration will be zero.
You are correct. We never demonstrated experimentally for gravity that the net gravitational force inside a sphere was zero. Of course, I never said we did. The term "demonstrate" can, in fact, be used in a mathematical sense. When one of the kids on our dorm floor claimed the Ringworld was unstable, we had no trouble demonstrating that instability -- not that anyone had a Ringworld to work with.
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What if (Score:5, Funny)
Re:What if (Score:5, Funny)
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Suspect this is rubbish - NS has been had? (Score:3, Insightful)
What exactly are they thinking of putting into orbit around this thing?
Re:Suspect this is rubbish - NS has been had? (Score:5, Informative)
No doubt. The only reason there is any hydrogen on *Earth* is because it binds readily with more massive elements. Helium does not and, as a consequence, any helium released into the atmosphere will ultimately escape. My understanding is that the only reason we have any helium at all is due to radioactive decay from heavier elements
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Re:Suspect this is rubbish - NS has been had? (Score:5, Informative)
I calculated the escape velocity using the formula sqrt(2Gm/r) [yale.edu]:
sqrt((2)(6.6742x10^-11)(5.16)/0.4) = 0.00013m/s or 0.013cm/s
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Sounds like a fancy version of... (Score:3, Interesting)
Simpson's... (Score:3, Funny)
interesting but (Score:5, Insightful)
Such experiments, while useful, aren't practical when we have a real and current need to figure out how to get construction workers and ordinary people into space, so we can build a realistic presence there.
Once we're there, we could perform experiments like this at a fraction of the cost.
Ok, perhaps I'm thinking too fancifully, but it's real concern. Let's face it, every environment we've moved into only becomes liveable when the ordinary people who know how to build stuff and make things arrive. The larger the number of people, the faster things progress.
So long as it's only scientists and the 'elite' going into space and performing experiments progress will be very slow. That can't be good.
What we need is people going 'prospecting' for interesting asteroids/orbiting 'junk' that can be exploited, building commercial stations, setting up routine flights into space. In short, we need economic forces active in space.
Too many uncertainties (Score:4, Interesting)
I wonder how they could conclude that a change of this magnitude would come from gravity leaking into other dimension and not from any of the other myriad of possible effects. It is a good idea, I just don't see how it could work.
High School Physics (Score:5, Informative)
Going with a circular orbit because they didn't specify the ellipse:
365.24*24*3600 = 31556736.00 seconds per year
1/. =
Pretty slow orbit. About that tungsten, 19250 kg/m3
3.1415926*(4/3)*.04*.04*.04 =
And let's say the planet is 8 mm in diameter,
3.1415926*(4/3)*.004*.004*.004 =
F = G m1 m2 / r^2 =
gravitational constant = 6.67300 × 10-11 m3 kg-1 s-2
=
Sounds reasonable to me. Assuming they can get a clean launch at exactly
Re:High School Physics (Score:4, Funny)
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Re:Outside effects? (Score:3, Informative)
Lagrangian Point [wikipedia.org]
Re:Why L2? (Score:5, Interesting)
So they've got that much of it thought out. But in regards to the mass of the spacecraft carrying this jar:
So while they're full aware of the problems the mass of the craft can cause, they seem to think it's possible to minimize the effects to a reasonable level.
My question is, aren't Lagrangian points going to start to get a bit crowded? There are only five to work with in our neighbourhood and who gets to say who uses which and for how long?
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Re:Risky (Score:3, Funny)
Re:What's tungsten? (Score:5, Funny)
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Gauss's Law (Score:5, Informative)
Gauss's Law [wolfram.com] says that the gravitational acceleration of a body anywhere in an enclosed sphere is 0. At L4, L5 Earth and Sun graviational forces are balanced. The only accelerations that don't cancel out are the two body accelerations of interest. It is surprising to me that the bodies orbit as fast as 10 times per day. I wonder why they don't use heavier Uranium as the mass. It is an interesting side note that a body can stably orbit one of these points. They orbit with no body (!) at the focus. The Genesis Probe and WMAP missions have already taken advantage of this.
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Re:Gauss's Law (Score:5, Informative)
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Re:Gauss's Law (Score:5, Informative)
No it doesn't, re=read the law you linked to. It says the "surface integral of gravitational acceleration" will be zero over any arbitrarily-shaped closed surface, as long as that surface encloses zero mass. You cannot work backwards from this statement to assume that the local gravitational acceleration will be zero.
Simple example. Imagine a closed surface (say a small sphere) 20 feet above the ground (and also assume there's no air inside) such that the surface is closed. Since it encloses no mass, the net acceleration will be zero as summed over the whole sphere. However, any object placed within this hypothetical spherical surface (eg a brick) will fall to the ground.
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