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Astronomers Claim Discovery of Earth-like Planet

Posted by CmdrTaco on Mon Jul 21, 2008 09:29 AM
from the that-would-be-a-rough-civ-map dept.
Raver32 writes "A team of astronomers announced they have discovered the smallest and potentially most Earth-like extrasolar planet yet. Five times as massive as Earth, it orbits a relatively cool star at a distance that would provide earthly temperatures as well, signaling the possibility of liquid water. 'The separation between the planet and its star is just right for having liquid water at its surface,' says astronomer and team spokesperson Stephane Udry of the Observatory of Geneva in Versoix, Switzerland. 'That's why we are a bit excited.' But researchers do not yet know if the planet contains water, if it is truly rocky like Earth, which might make it hospitable to life as we know it, or whether it is blanketed by a thick atmosphere. 'What we have,' Udry says, 'is the minimum mass of the planet and its separation" from its star.'"
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  • TFA (Score:5, Informative)

    by bsDaemon (87307) on Monday July 21 2008, @09:32AM (#24273759) Homepage

    TFA is dated 24 April, 2007 -- I'm pretty sure that this is old news.

  • Interesting find. (Score:3, Interesting)

    by sneezinglion (771733) on Monday July 21 2008, @09:33AM (#24273777)

    I wonder how long before we can verify an earth like extrasolar planet?

    As more of these are found we may be able to plug more data into drake's equation [wikipedia.org]

    • Re:Interesting find. (Score:5, Interesting)

      by WibbleOnMars (1129233) on Monday July 21 2008, @09:49AM (#24274049)

      Since Drake's equation needs to know the proportions of stars with planets, it would require us to have known negative results as well as known positives in order for it to give any meaningful results.

      At the moment, we can say there are a few hundred planets, out of maybe a few thousand stars that we've scanned, but for the stars where we haven't found anything, we don't know for sure whether that's because there isn't anything there, or because we just aren't looking hard enough.

      • by edalytical (671270) on Monday July 21 2008, @11:35AM (#24276209) Homepage Journal
        Forget the proportion of stars with planets. Fl is the real unknown. Why assume all planets that can support life will develop life? What if life is actually pretty rare? Try plugging in values less that 1 for Fl (0.1, 0.01, 0.001) and you'll get some disappointing results from this equation. Trying to quantify something with so many unknowns seems pretty silly to me. On the other hand maybe life isn't rare, but that's just me being hopeful.
  • by Fallen Andy (795676) on Monday July 21 2008, @09:53AM (#24274133)
    can be found here [wikipedia.org](Gliese 581) and here [wikipedia.org](Gliese 581c). It's a sad day when wikipedia seems to be more reliable than SciAm, but oh well, the rot set in many years ago...

    Andy

  • by sjonke (457707) on Monday July 21 2008, @09:58AM (#24274229) Journal

    Invade!

  • by bersl2 (689221) on Monday July 21 2008, @10:08AM (#24274443) Journal

    That's kind of important, I would think.

  • Assuming that the density is a little bit less than the Earth (more like the Moon or Mars) and this "Super Earth" is thus larger by a sizable fraction..... what is the geological environment of a planet such as this like?

    Since the interior heat of this planet has less surface area in proportion to its volume, internal heat from its formation and nuclear decay from heavy elements (like Uranium) would therefore cause a much larger interior heat sink... and causing substantially more techtonic activity and a great many more volcanoes.

    Using Mars as a comparator here as well, Mars is smaller than the Earth, and geologically dead, with fewer but much larger volcanoes. Is it reasonable to assume this planet... if it had a rocky "surface", would literally be littered with smaller volcanoes over nearly all of its surface with much smaller "continents"?

    Assume that the age of this planet is roughly similar to that of the Earth and that heavy metals (heavier than Iron) in its formation are roughly proportional to what we find on the Earth.

    I just don't find that this would be all that pleasant of a place to be at, and the nearly constant volcanism would IMHO kill off nearly any attempt to colonize this planet with life.

    It certainly would be a weird planet to look at though.

    • The latest results of Messenger's first flyby of Mercury confirms a magnetic field and molten outer core. Conversely, Venus which is Earth's twin in size, seems a lot more dead. A more important factor may have been chemical composition at the time of formation - Mercury had more metal. Elements may have been unevenly distributed as function of distance from the Sun in the original planetary nebula.
  • by oldspewey (1303305) on Monday July 21 2008, @12:59PM (#24277769)

    To the many, many people who've taken the time to correct my shitty assumption, berate me, mod me down, and otherwise point out that in my rush to post I forgot to turn my brain on ... I hang my head in shame. I will now seek out my grade 10 physics teacher (or locate his grave as the case may be) and confess my sins.

    And of course, for the angriest among you, this post presents another opportunity to mod me down.

    • by CastrTroy (595695) on Monday July 21 2008, @09:32AM (#24273755) Homepage
      That's only if the radius from the centre of the objects is the same. Remember, gravity decreases as a function of the square of the distance.
      • Re: (Score:3, Informative)

        It's a poorly written and shite article, but the box off to the side says:

        One of two newly discovered exoplanets is nearly the size of Earth...

        So, assuming they're talking about the same one, it should be roughly 5 times our gravity.

        • Re: (Score:3, Informative)

          It's a poorly written and shite article, but the box off to the side says:

          One of two newly discovered exoplanets is nearly the size of Earth...

          So, assuming they're talking about the same one, it should be roughly 5 times our gravity.

          The Earth has a density of about 5.5, so if that planet was 5 times heavier than Earth, it would have a density of 27.5 am I right? Even if it was made of pure gold it couldn't be that dense.

          • by CheshireCatCO (185193) on Monday July 21 2008, @10:21AM (#24274713) Homepage

            Yeah, that's an unreasonable density, but you should bear in mind that compression occurs. (Earth's uncompressed density is significantly lower than the actual density, for example.)

            That said, you can fairly assume that the density is nearly the same as Earth's. In that case, the surface gravity is only about 70% higher than here. It'd still be tough walking around.

            • So what you're saying is we should go there to work out?
              • by Tweenk (1274968) on Monday July 21 2008, @11:29AM (#24276035)

                Uncompressed density = density of material at 1 atm
                Compressed density = density of material under given pressure

                If we took all the stuff Earth is made of, took it apart and measured the average density of all those rocks at 1 atm, we would get a significantly lower average than what we get by dividing the estimated mass of Earth by its estimated volume.

          • by Bobby Mahoney (1005759) on Monday July 21 2008, @10:26AM (#24274813)
            When they say "nearly the size of earth" they're speaking in an astronomical scale, which would qualify something 5-times as large as the earth as 'nearly'. It's not composed of gold or other heavy metal.
            • by Red Flayer (890720) on Monday July 21 2008, @11:19AM (#24275815) Journal

              It's not composed of gold or other heavy metal.

              Says you.

              We don't know what it's composed of, and it *could* be solid gold. It *could be* heavy metal.

              I personally believe it's composed entirely of soft rock. Chances are very slim that it's composed of top-40 pop or country&western.

        • by zacronos (937891) on Monday July 21 2008, @10:46AM (#24275179)

          It's a poorly written and shite article, but the box off to the side says:

          One of two newly discovered exoplanets is nearly the size of Earth...

          So, assuming they're talking about the same one, it should be roughly 5 times our gravity.

          Not so. If the planet has twice the diameter of earth, that falls well within the category of "nearly the size of Earth" for astronomers. Since gravity decreases proportionally to the square of the distance, gravity would be only 5/(2^2) times as strong as on Earth, an increase of a mere 20%.

          If it has approximately the same density as earth, then since volume of a sphere increases proportionally to the cube of the radius/diameter, it would have 5^(1/3) times as large a diameter as earth, which is about 1.71 -- even closer to the size of our Earth. It would also wind up with gravity 1.71 times as strong, since 5/((5^(1/3))^2) == 5/(5^(2/3)) == 5^(1/3).

          • Re: (Score:3, Insightful)

            you're both missing the point, if the planet has water, then the only factor is compression ratio, aquatic life don't suffer from gravity like land bound creatures do, if they have neutral buoyancy the only effect of gravity they feel is the relative pressure of the water at the depth they live in.

            considering there are whales that can go very deep in the ocean, to the very surface, the pressure regulation seems to be easily solved.

            gravity only becomes an issue when life tries to evolve from aquatic life to

      • by oldspewey (1303305) on Monday July 21 2008, @09:41AM (#24273927)

        I think that in planetary terms we can safely assume 5x mass will create an environment of roughly 5g ... maybe give or take 20%. Enough to ensure that the simple act of getting out of bed would be a gruelling ordeal.

        Another problem I noticed after actually reading TFA:

        Gliese 581 c, orbits at one fourteenth the distance between Earth and the sun. But the red dwarf is 50 times cooler than the sun. The group estimates that the planet would experience temperatures in the zero-to-40-degree-Celsius (32-to-104-Fahrenheit) range.

        It is my understanding that red dwarfs, while generating reduced heat and light output, produce solar flares that are almost as intense as those produced by a G class star. So if a planet exists in the habitable zone it is also exposed to periodic sterilizing blasts of charged particles.

        Maybe if we're lucky the planet happens to have a really strong magnetic field ... then we just have the crushing g load to contend with.

        • by jayhawk88 (160512) <rockchalk88@yahoo.com> on Monday July 21 2008, @09:56AM (#24274187) Homepage

          Plus you can take into account all the other advantages life on Earth has had to make it possible:

          - In a solar system with a large gas giant, which helps keep catastrophic impacts with asteroids and comets from happening too often

          - Has a large satellite, which may help stabilize climate

          - Is in a quiet part of the galaxy, and is not too near other stars, avoiding interactions with other stars/gamma ray bursts/etc.

          • Re: (Score:3, Interesting)

            These points, among others, are made by authors Ward and Brownlee in the book Rare Earth

            Long story short, complex life as it exists here on Earth is the result of a long series of very happy accidents. The odds against it happening elsewhere are ... well ... astronomical.

            • by Ihlosi (895663) on Monday July 21 2008, @10:15AM (#24274581)

              The odds against it happening elsewhere are ... well ... astronomical.

              The universe contains a very large number of elsewhere.

              • Re: (Score:3, Interesting)

                The universe contains a very large number of elsewhere.

                In fact, I would argue that from a human sized point of view, it contains an astronomical number of elsewheres.

            • "Space is big. Really big. You just won't believe how vastly, hugely, mind-bogglingly big it is." ...and thats the thing about a really big place- sheer size provides an astronomical number of opportunities for such astronomically unlikely things to happen, over and over agin.
        • by Anonymous Coward on Monday July 21 2008, @10:15AM (#24274595)

          I think that in planetary terms we can safely assume 5x mass will create an environment of roughly 5g ... maybe give or take 20%. Enough to ensure that the simple act of getting out of bed would be a gruelling ordeal.

          I don't know about you, but getting out of bed is a grueling ordeal at any gravity for me!

        • by Grokmoo (1180039) on Monday July 21 2008, @10:26AM (#24274797)

          I think that in planetary terms we can safely assume 5x mass will create an environment of roughly 5g ... maybe give or take 20%. Enough to ensure that the simple act of getting out of bed would be a gruelling ordeal.

          Another problem I noticed after actually reading TFA:

          No, it would not. It would need to be much denser than Earth for that to happen. This is basically impossible for an object of that mass.

          Assuming roughly Earth like density (which is quite plausible), Radius will scale like Mass to the 1/3, while gravity scales like mass / radius squared. This works out to about 1.7 times Earth gravity at the surface.

        • by flabbergasted (518911) on Monday July 21 2008, @10:32AM (#24274935)

          Oh for god's sake, people! Do a little math.

          Let's assume that the average density of the earth-like planet is the same as Earth. (It wouldn't be an earth like planet if it were significantly different.) Then we can use the volume of the sphere to relate the mass and the surface radius. Since M = 4/3 * \pi * R^3 * \rho, where \rho is the density, it is easy to see that the surface radius goes like the cube root of the mass. Putting this into Newton's equation, we can see that a = GM/R^2 means that the surface gravity is also going to go like the cube root of the mass. If the mass is five times that of Earth, then the surface gravity will be the cube root of 5 greater than Earth's or about 1.7 times Earth normal.

          Taking differences in the mean density into account is no more difficult, but I leave that as an exercise for the reader.

          • Re: (Score:3, Interesting)

            Even without doing any maths, some basic sanity checking can tell the grandparent that he's an idiot. Gravity on the surface of Jupiter is about 2.3 times that on Earth and Jupiter is a shade under 320 times the mass of the Earth. A planet with five times the surface gravity of Earth would have to be incredibly dense.
        • I think that in planetary terms we can safely assume 5x mass will create an environment of roughly 5g ... maybe give or take 20%.

          How do you justify that remark? Mars [wikipedia.org] has a mass 1/9 of Earth's but a surface gravity over 1/3 of Earth's. Mercury [wikipedia.org] has a mass 1/18 that of Earth but has gravity slightly higher than that of Mars.

          There's just no way you can have confidence within 20% that the gravity will be proportional to the mass.

        • Re: (Score:3, Informative)

          No. While it is hard to measure, gravity drops off with any altitude at all. The gravity you feel standing on top of Mt. Everest is ever so slightly less than that in Death Valley.

        • by AdamHaun (43173) on Monday July 21 2008, @09:56AM (#24274183)

          You're probably thinking of the shell theorem, which says that a uniform sphere of mass is gravitationally equivalent to a point mass located at the center of the sphere. This theorem does imply that a larger radius = less gravity at the surface.

        • by the_other_chewey (1119125) on Monday July 21 2008, @10:00AM (#24274265)
          To calculate the gravitational effect of a massive sphere, its whole mass can be
          considered accumulated in its center as long as you are outside of it.
          So the gravitational acceleration indeed only depends on mass an distance.
          Mathematical fact.

          Neat additional trivia:
          - Inside a hollow sphere, there is no gravitational effect by the sphere's mass - it cancels out exactly.
          That's why
          - Inside a massive sphere, gravitational acceleration increses linearly with the radial distance to the center.
          (the mass increases with r^3 as you get further out, its effect decreases by 1/r^2 - and as it can be considered
          concentrated in the middle, you get an increase by a factor of r^3/r^2 = r
          Gravity is fun :-)

          All this of course only for constant density.
    • Re: (Score:3, Informative)

      5x gravity only if it were the same physical size.

    • It may be earthlike, but it sure wouldn't be a comfortable place to spend any amount of time.

      For you maybe, but anything that evolved in that environment would be really strong on this planet, be able to leap...wait, what was the name of that planet?

      Can you imagine the women, why they'd be build like a brick shi...cue the Commodores.

    • Nope. (Score:5, Informative)

      by Ihlosi (895663) on Monday July 21 2008, @09:38AM (#24273879)
      It may be earthlike, but it sure wouldn't be a comfortable place to spend any amount of time.

      Mass alone says very little about the surface gravity of a planet - you need to know the radius of the object to make any statement about its surface gravity. Earth's moon has slightly over a percent of the mass of Earth, but about 1/6g surface gravity. Mars has only about 10% of the mass of Earth, while having 1/3g surface gravity.

    • by 4D6963 (933028) on Monday July 21 2008, @09:48AM (#24274033)

      From the blurb itself, it's five time the size of earth, it's revolving around a cooler sun than earth, and it might not have liquid water or a thick atmosphere. Yeah, that's exactly like earth!

      You're missing the point. By Earth-like they mean telluric planet, as in, not a gas giant. That's all. And that matters because until now we haven't found so many of them, most of the planets we've found were gas giants orbiting close to their star. But as time goes by we find ever decreasingly large planets that get closer and closer to the Earth in size.


      • You're missing the point. By Earth-like they mean telluric planet, as in, not a gas giant.

        In this case, they don't actually mean even this. From TFA:

        "What we have," Udry says, "is the minimum mass of the planet and its separation" from its star.

        They don't actually know if it's rocky. All that they know is that the mass is about right, and it's about close enough to a red dwarf for liquid water.
    • by gardyloo (512791) on Monday July 21 2008, @01:40PM (#24278371)

      No, no, no. Fill it with hairdressers, tired TV producers, insurance salesmen, personnel officers, security guards, management consultants, and telephone sanitizers.

        • Re: (Score:3, Insightful)

          You mean dead, desiccated prisoners. How long would it take Voyager to travel 20 ly? And we want to send people on that trip? Do we tell them we're going to use a worm hole/star gate/warp drive on the ship and that's why they're only getting a single soda and pack of peanuts for supplies?